Page 96 - Mechanical Engineers' Handbook (Volume 4)
P. 96

11 Viscous Fluid Flow in Ducts  85
                                                 p   p     Vp     L   2ln
                                                                          p
                                                                           2
                                                  2
                                                      2
                                                            2
                                                                 ƒ
                                                          1
                                                            1
                                                      2
                                                  1
                                                              1
                                                                  D       p 1
                           or, in terms of the initial Mach number,
                                                 p   p   kM p     L   2ln
                                                                          p
                                                                           2
                                                      2
                                                              2
                                                  2
                                                            2
                                                                ƒ
                                                              1
                                                            1
                                                  1
                                                      2
                                                                  D       p 1
                           The downstream pressure p at a distance L from section 1 may be obtained by trial by
                                                 2
                           neglecting the term 2 ln(p /p ) initially to get a p , then including it for an improved value.
                                                  1
                                                                  2
                                               2
                           The distance L is a section where the pressure is p is obtained from
                                                                   2
                                                                   2
                                                                p
                                                       1
                                                  L                        p 1
                                                                 2
                                                 ƒ         1            2ln
                                                  D   kM  2 1   p 1        p 2
                              A limiting condition (designated by an asterisk) at a length L* is obtained from an
                           expression dp/dx to get
                                                  dp    pƒ/2D    (ƒ/D)( V /2)
                                                                         2

                                                                      2
                                                  dx  1   p/ V  2  kM   1
                           For a low subsonic flow at an upstream section (as from a compressor discharge) the pressure
                           gradient increases in the flow direction with an infinite value when M*   1/ k    0.845
                           for k   1.4 (air, for example). For M approaching zero, this equation is the Darcy equation
                           for incompressible flow. The limiting pressure is p*   p M  k,  and the limiting length is
                                                                        1
                                                                          1
                           given by
                                                    ƒL*    1           1
                                                                1   ln
                                                     D    kM  2 1     kM  2 1
                           Since the gas at any two locations 1 and 2 in a long pipe has the same limiting condition,
                           the distance L between them is

                                                    ƒL    ƒL*       ƒL*
                                                    D      D         D
                                                              M 1       M 2
                           Conditions along a pipe for various initial Mach numbers are shown in Fig. 35.
                              For adiabatic flow the limiting Mach number is M*   1. This is from an expression
                           for dp/dx for adiabatic flow:
                                     dp    ƒkp M   1   (k   1)M  2    ƒ  V  2   1   (k   1)M  2
                                                 2
                                     dx     2D        1   M  2      D 2       1   M  2
                           The limiting pressure is
                                                                 1
                                                  p*        2[1   ⁄2(k   1)M ]
                                                                          2
                                                                          1
                                                       M
                                                  p 1    1       k   1
                           and the limiting length is
                                            ¯
                                            ƒL*   1   M  2  k   1     (k   1)M  2
                                                       1        ln           1
                                                                                2
                                                                       1
                                             D     kM  2 1  2k    2[1   ⁄2(k   1)M ]
                                                                                1
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