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Chapter 7.  Environmental. special loading,and manufacturing <fleets   313


                                                                              (7.27)


            Total (elastic and temperature) generalized strains ET,  yT and KT entering Eqs. (7.23)
            and (7.24) can be expressed in  terms  of displacements and rotation  angles of the
            laminate element with the aid of Eqs. (5.3) and (5.14), i.e.

                                                                              (7.28)


                                                                              (7.29)


                                                                              (7.30)

            As  follows  from  Eqs. (7.23),  in  the  general  case,  uniform  heating  of  laminates
            induces in contrast to homogeneous materials, not only in-plane strains but also the
            changes of  laminate curvatures and twist. Indeed, assume that the laminate is free
            from the edge and surface loads so that forces and moments in the left-hand sides of
            Eqs. (7.23)  are equal  to zero.  Because CTE of the layers, in the general case, are
            different, thermal terms NT and MT in the right-hand  sides of  Eqs. (7.23) are not
            zero even for the uniform temperature field, and these equations allow us  to find
            ET,  yT  and  KT  specifying  the  laminate  in-plane  and  out-of-plane  deformation.
            Moreover,  using  the  approach  described  in  Section  5.10  we  can  conclude  that
            uniform  heating  of  the laminate  is accompanied, in  the general  case,  by  stresses
            acting in the layers and between the layers.
              As  an  example,  consider  the  four-layered  structure  of  the  space  telescope
            described in Section 7.1.1.
              First, we calculate the stiffness coefficients of the layers, Le.:
            0  for the internal layer of aluminum foil:




            0  for the inner skin:



            0  for the lattice layer:

                         6
                A\:'  = 2E,.Lcos4 4,.  = 14.4 GPa,
                         a,.
                         Sr
                A$  = 2Er -sin4$r  = 0.25 GPa,
                         a,.
                         6
                A\:'  = 2E,.Lsin'  $cos'  $ = I .91 GPa  ,
                         ar
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