Page 400 - Mechanics Analysis Composite Materials
P. 400

Chapter 8.  Optimal composite StrucIures       385

            The solution of this equation that satisfies the boundary condition +(r= R) = 4Ris
            presented  as follows:







            As has been already noted in the previous section, the simplest and rather adequate
            model of unidirectional fibrous composites for design problems is the monotropic
            model ignoring the stiffness of the matrix.  For this model, we should take n = 0 in
            the foregoing equations. Particularly, Eq. (8.58) yields in this case
               r sin 4(r) = R sin 4R .                                        (8.59)


            This is the equation  of a  geodesic line on the surface of revolution. Thus, in  the
            optimal filament wound shell the fibers are directed  along the geodesic lines. This
            substantially simplifies the winding process because the tape placed on the surface
            under  tension  automatically  acquires  the form of the  geodesic line if  thcrc  is no
            friction between the tape and the surface.
              As  follows from  Eq. (8.59), for 4 = 90”, the tape touches  the  shell parallel  of
            radius
               r0  = R sin 4R                                                 (8.60)

            and the polar opening of this radius is formed in the shell (see Fig. 8.4).
              Transforming Eq. (8.48) with the aid of Eqs. (8.59) and (8.60) and taking n = 0
            we  arrive  at  the  following  equation  that  specifies the  meridian  of  the  optimal
            filament wound shell:


                                                                              (8.61)



            where
                ,  ,  2T
               q- = r;  - - r0  .                                             (8.62)
                        P
            Integrating  Eq. (8.61)  with  due  regard  for  the  condition  l/z’(R) = 0  which,
            as earlier, requires that for r = R  the tangent to the meridian be parallel to z-axis,
            we get


                                                                              (8.63)
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