Page 402 - Mechanics Analysis Composite Materials
P. 402

Chapter 8. Optimal composite structures        387

            i.e., under axial tension, a hyperbolic shell is obtained with the meridian determined
            as

               r'  - 2 tan2 4R = R'  .

            This meridian corresponds to line  1 in Fig. 8.6. For 4R = 0, the hyperbolic shell
            degenerates into a cylinder (line 2). Curve 3 corresponds to T = pr0/2, i.e., to a shell
            for  which  the  polar  opening  of  radius  r0  is  closed.  For  the  special  angle
            4R = 4o = 54"44',  the  shell  degenerates into  a  circular  cylindrical shell  (line  2)
            discussed in section 8.1. For T = 0, Le., in case of an open polar hole, the meridian
            has the form corresponding to curve 4. The change in the direction of axial forces T
            yields a toroidal shell (line 5). Performing integration of Eq. (8.65) and introducing
            dimensionless parameters




            we  finally arrive at

                       -7
               -
               z=-   - '- F(k, 0) + d=E(k,   0)  ,                            (8.67)
                   d-
            where


                                                 J
               F(k,B) =                  E(k, 0) =  d1 - k2 sin'  0 de
                        0                        0
            are the first-kind and the second-kind elliptic integrals and



                kl 2  =






            As an application of the foregoing equations, consider the optimal structure of the
            end closure of the pressure vessel  shown in  Fig, 4.14. The cylindrical part  of  the
            vessel consists of zk4R angle-ply layer with thickness  la^,  that can be  found from
            Eq. (8.64) in which we should take T = pr0/2, and a circumferential (4 = 90") layer
            whose thickness is specified by  Eq. (8.18),  i.e.
               h90  = h&cos2  4R - 1)  .

            The polar opening of the dome (see Fig. 4.14) is closed. So T = pr0/2, fj = 0, and the
            dome meridian corresponds to curve 3 in Fig. 8.6. As has already been noted, upon
   397   398   399   400   401   402   403   404   405   406   407