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158                                                         Chapter 3



















                  Figure 3.28 Short leg’s length as a function of the long leg’s length

         Example 3.10
             Compare the  total axial  stiffness of a  serpentine spring  which has  5
         linearly-scaled units to the axial stiffness of another serpentine spring which
         contains 5 identical units. The width of the third (middle) unit in the scaled
         version is  equal to the  width of the units  in the  other design,  which is
         Assume the  two  configurations are  built of  the  same material and  have
         identical constant rectangular cross-sections. The legs are defined by
             and

          Solution:
             The total  stiffness of each configuration is  given by  the  rule of series
         connection (which is also treated in Chapter 5) and therefore its expression is
         determined as:







          For the configuration with  identical units the,   factors of Eq.  (3.85)  are
          identical, and can  be  calculated by  inverting the compliance   of  Eq.
          (3.75) with the  appropriate length  For  the  scaled  version, one  needs to
          calculate the length   for each of the units. It is known that the length of the
          unit in the middle of the second design is equal to the length of the identical
          units in the first design, namely.





          The lengths of the other four units can be calculated with the aid of Fig. 3.26
          as:
   166   167   168   169   170   171   172   173   174   175   176