Page 227 - Modeling of Chemical Kinetics and Reactor Design
P. 227

Reaction Rate Expression  197
                                        −
                                     =  21  ×   1   ×  1
                                               .
                                        1     0 022   5
                                       .
                                     = 909 lgmol •min

                              At 110°C, C    = 0.025 gmol/l, t  = 2 min, and
                                          AO                 1/2
                                        −
                                 k   =  21  ×  1   ×  1
                                  110
                                               .
                                        1     0 025  2
                                     = 20 l gmol•min

                                The activation energy and frequency factor  can be determined from
                              the Arrhenius equation


                                 k =  k exp   − E 
                                  T   O      RT                                       (3-290)


                              where k  = rate constant at known temperature
                                     T
                                    k  = frequency factor
                                     O
                                     E = activation energy
                                     R = ideal gas constant 1.987cal/mol • K


                                              − E 
                                 k   =  k exp      
                                              R 373)
                                  100  O       (                                        (3-291)

                                              − E 
                                 k 110  =  k exp                                      (3-292)
                                               (
                                       O
                                              R 383)
                                Dividing Equation 3-291 by Equation 3-292 gives


                                                 (
                                 k 100  =  exp  − (  ER 373))
                                                 (
                                 k 110  exp  − (  ER 383))                              (3-293)

                                Removing the exponential, Equation 3-293 can be expressed as
   222   223   224   225   226   227   228   229   230   231   232