Page 230 - Modeling of Chemical Kinetics and Reactor Design

200 Modeling of Chemical Kinetics and Reactor Design

The rate constant k is
1
θ + X
A
ln B( B X )
θ
k = C ( AO + 1− BO A t
C )
1

= ln ( .0 75 0 .035 )
) ( )
( .0 495 1

−
= 6 191 l gmol hr
.
−
= 62 l gmol hr
.
The rate equation is

.
− ( r )=− dC A = 62 CC l
A A B
dt gmol − hr
The rate is at maximum when C = C . From stoichiometry:
A
B
C − C = C − C
AO A B BO
and

C + C = C AO + C BO
A
B
.
= (0 45 + 0 045 )
.
= 0 495
.
Therefore,

1
C = C = ×0 495.
A B
2
= 0 2475.

The corresponding fractional conversion X is
A