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1400-CH08  9/9/99  2:18 PM  Page 251






                                                                         Chapter 8 Gravimetric Methods of Analysis  251

                     EXAMPLE 8.1
                     An ore containing magnetite, Fe 3 O 4 , was analyzed by dissolving a 1.5419-g
                                                                       3+
                     sample in concentrated HCl, giving a mixture of Fe 2+  and Fe . After adding
                                              3+
                     HNO 3 to oxidize any Fe 2+  to Fe , the resulting solution was diluted with water
                     and the Fe 3+  precipitated as Fe(OH) 3 by adding NH 3 . After filtering and
                     rinsing, the residue was ignited, giving 0.8525 g of pure Fe 2 O 3 . Calculate the
                     %w/w Fe 3 O 4 in the sample.
                     SOLUTION
                     This is an example of a direct analysis since the iron in the analyte, Fe 3 O 4 , is
                     part of the isolated precipitate, Fe 2 O 3 . Applying a conservation of mass to Fe,
                     we write

                                         3 ´moles Fe 3 O 4 =2 ´moles Fe 2 O 3
                     Using formula weights, FW, to convert from moles to grams in the preceding
                     equation leaves us with

                                                3
                                                             2
                                         3 ´g Fe O 4  2 ´g Fe O 3
                                                    =
                                               3
                                                            2
                                            FW Fe O 4  FW Fe O 3
                     which can be solved for grams of Fe 3 O 4 and %w/w Fe 3 O 4 in the sample.
                                             2 ´ 0 8525 g  ´231.54 g/mol
                                                 .
                     2 ´g Fe O 3  ´FW Fe O 4
                                       3
                            2
                                           =                         = .         3
                                                                       0 82405 g Fe O 4
                                  2
                          3 ´FW Fe O 3            3  ´159.69 g/mol
                                               .
                                              0 82405  g
                                   3
                               g Fe O 4  ´100  =        ´100  =53 44.%  w/w Fe
                                 g sample      1.5419 g
                 As discussed earlier, the simultaneous analysis of samples containing two analytes
                 requires the isolation of two precipitates. As shown in Example 8.2, conservation of
                 mass can be used to write separate stoichiometric equations for each precipitate.
                 These equations can then be solved simultaneously for both analytes.
                     EXAMPLE 8.2
                     A 0.6113-g sample of Dow metal, containing aluminum, magnesium, and other
                     metals, was dissolved and treated to prevent interferences by the other metals. The
                     aluminum and magnesium were precipitated with 8-hydroxyquinoline. After
                     filtering and drying, the mixture of Al(C 9 H 6 NO) 3 and Mg(C 9 H 6 NO) 2 was found
                     to weigh 7.8154 g. The mixture of dried precipitates was then ignited, converting
                     the precipitate to a mixture of Al 2 O 3 and MgO. The weight of this mixed solid was
                     found to be 1.0022 g. Calculate the %w/w Al and %w/w Mg in the alloy.

                     SOLUTION
                     This is an example of a direct analysis in which the two analytes are determined
                     without a prior separation. The weight of the original precipitate and the
                     ignited precipitate are given by the following two equations
                                     g Al(C 9 H 6 NO) 3 + g Mg(C 9 H 6 NO) 2 = 7.8154

                                          g Al 2 O 3 + g MgO = 1.0022
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