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Chapter 6  Fourier, Taylor, and Maclaurin Series


                Example 6.13
                Express the function

                                                    y =  f t() =  e t                                 (6.131)
                in a Maclaurin’s series.

                Solution:

                A Maclaurin’s series has the form of (6.132), that is,
                                                                          n ()
                                                                             0 () n
                                                           ------------x +
                                     fx() =  f0() +  f' 0()x +  f'' 0() 2  … +  f -----------------x  (6.132)
                                                            2!            n!
                                                                                                     t
                                                                                                    e
                For this function, we have  ft() =  e t  and thus f0() =  1 . Since all derivatives are  , then,
                f' 0() =  f'' 0() =  f''' 0() =  … =  1  and therefore,
                                                                  3
                                                             2
                                                                 t
                                                             t
                                               f t() =  1 ++  ----- +  ----- +  …                     (6.133)
                                                          t
                                               n
                                                             2!
                                                                 3!
                MATLAB displays the same result.
                t=sym('t'); fn=taylor(exp(t)); pretty(fn)
                                   2        3         4          5
                      1 + t + 1/2 t  + 1/6 t  + 1/24 t  + 1/120 t

                Example 6.14

                In a semiconductor diode  , the instantaneous current i D   and voltage v D  are related as
                                         D
                                                              v  ⁄  nV
                                                 i (  D  v )  D  =  I e  D  T                         (6.134)
                                                            D
                where I D  is the DC (average) component of the current, the constant   has a value between 1
                                                                                     n
                and   depending on the material and physical structure of the diode, and V T  is the thermal volt-
                    2
                age which depends on the temperature, and its value at room temperature is approximately

                25 mV  .
                Expand this relation into a power series that can be used to compute the current when the volt-
                age is small and varies about v D  =  . 0

                Solution:

                Since the voltage is small and varies about v D  =  0 , we can use the following Maclaurin’s series.





               6−46                             Numerical Analysis Using MATLAB® and Excel®, Third Edition
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