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324     7 Probability theory and stochastic simulation



                      t  A
                      A              t    =    in
                                     B        A
                      A  1 a       a   1 a      a
                                 2             2
                                              aa
                                a
                       t
                       A
                                   1 a
                                                         2
                         in                 aa
                         B
                                         2
                                   a
                   Figure 7.5 Expected weights looking “out” or “in” from functional groups.
                   We first consider E(W|M 1 ). If we select a type-1 unit, the mass W of the chain must at
                   least equal the mass M 1 of a single type-1 unit, as well as the contributions from the masses
                   observed by looking “outwards” from each of the α 1 acid groups (Figure 7.5). E(W  out )is
                                                                                      A
                   the expected weight of the section of chain attached to a type-1 unit through one of its acid
                   groups. Thus,
                                                                out
                                          E(W|M 1 ) = M 1 + α 1 E W                   (7.30)
                                                                A
                   Similarly, the expected weight observed if we select a type-2 monomer equals the weight of
                   a single type-2 monomer unit plus the expected weights E(W out ) looking outwards across
                                                                    B
                   each of the β 2 base groups:
                                                                out
                                          E(W|M 2 ) = M 2 + β 2 E W                   (7.31)
                                                                B
                   To compute E(W out ), we note that a randomly-selected acid group must be either reacted
                                A
                   or unreacted, so that we expand in the possible outcomes:
                                      out       out              out
                                  E W    = E W   |L P(L|a) + E W   |A P(A|a)          (7.32)
                                      A        A                A
                   If the selected acid group is unreacted, there is no chain attached to this group and
                   E(W out |A) = 0. Also, as P(L|a) = p A ,wehave
                       A
                                               out        out
                                           E W    = E W                               (7.33)
                                               A        A  |L × p A
                   Next, from Figure 7.5, we note that the expected weight looking “out” from an acid group
                   on monomer 1 equals the expected weight observed looking “in” from a base group on a
                   monomer of type 2, and hence

                                       out         in                   out
                                   E W   |L = E W    = M 2 + (β 2 − 1)E W             (7.34)
                                       A          B                    B
                   Here, we have used the fact that if we come “in” across one of the base groups, there are
                   only (β 2 − 1) other possible ways to go “out.” Combining (7.33) and (7.34) yields
                                 out       in                          out
                            E W     = E W   × p A = p A M 2 + (β 2 − 1)E W            (7.35)
                                A         B                           B
                   Applying the same logic to E(W B out ),

                                 out        in                         out
                            E W     = E W    × p B = p B M 1 + (α 1 − 1)E W           (7.36)
                                B         A                           A
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