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6.3 The radial equation                     163

                        Ladder operators
                        We now solve equation (6.24) by means of ladder operators, analogous to the
                        method used in Chapter 4 for the harmonic oscillator and in Chapter 5 for the
                                                                        ^
                                                                  ^
                                          1
                        angular momentum. We de®ne the operators A ë and B ë as
                                                         d    r
                                                 ^
                                                A ë  ÿr     ÿ ‡ ë ÿ 1                    (6:26a)
                                                         dr   2
                                                        d   r
                                                ^         ÿ ‡ ë                          (6:26b)
                                                B ë   r
                                                       dr   2
                                                                         ^
                                                       ^
                          We now show that the operator A ë is the adjoint of B ë and vice versa. Thus,
                                      ^
                               ^
                        neither A ë nor B ë is hermitian. For any arbitrary well-behaved functions f (r)
                        and g(r), we consider the integral
                              …                     …             …
                               1                     1    dg        1     r
                                      ^
                                 f (r)[A ë g(r)] dr ˆÿ  f r  dr ‡     f ÿ ‡ ë ÿ 1 g dr
                               0                     0    dr       0      2
                        where (6.26a) has been used. Integration by parts of the ®rst term on the right-
                        hand side with the realization that the integrated part vanishes yields
                                 …            …                …
                                  1             1   d            1     r
                                     ^
                                    f A ë g dr ˆ  g   (rf )dr ‡    f ÿ ‡ ë ÿ 1 g dr
                                  0            0   dr           0      2
                                              …
                                                1      d   r
                                            ˆ    g r     ÿ ‡ ë f dr
                                               0      dr   2
                        Substitution of (6.26b) gives
                                        …                    …
                                         1                    1
                                                ^                    ^
                                           f (r)[A ë g(r)] dr ˆ  g(r)[B ë f (r)] dr       (6:27)
                                         0                    0
                        showing that, according to equation (3.33)
                                                      ^
                                                 ^
                                                                    ^
                                                               ^
                                                  y
                                                                y
                                                 A ë ˆ B ë ,  B ë ˆ A ë
                          We readily observe from (6.26a) and (6.26b) that
                                                  d 2      d         r 2
                                      ^ ^       2    ÿ 2r    ÿ ër ‡    ‡ ë(ë ÿ 1)        (6:28a)
                                      B ë A ë ˆÿr
                                                  dr 2    dr         4
                                ^ ^
                                A ë B ë ˆÿr 2  d 2  ÿ 2r  d  ÿ (ë ÿ 1)r ‡  r 2  ‡ ë(ë ÿ 1)  (6:28b)
                                            dr 2    dr              4
                        Equation (6.24) can then be written in the form
                                            ^ ^
                                            B ë A ë S ël ˆ [ë(ë ÿ 1) ÿ l(l ‡ 1)]S ël      (6:29)
                                                                                    ^ ^
                        showing that the functions S ël (r) are also eigenfunctions of B ë A ë . From
                        equation (6.28b) we obtain
                        1  We follow here the treatment by D. D. Fitts (1995) J. Chem. Educ. 72, 1066. However, the de®nitions of the
                         lowering operator and the constants a ël and b ël have been changed.
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