Page 194 - Petroleum Geology
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             will  be  20.1  MPa  (2915 psi) before the well is put onto production.  If  the
             tubing is now swabbed to oil, the static pressure at the well head will be:

             p =  (p,  - po) gz =  4.7 MPa  =  682 psi.                       (8.11)
             This pressure is unbalanced,  so the well will  flow if the valve is opened. The
             rate at which the well will flow depends on the energy losses in the entire sys-
             tem - energy lost by flow to the well, and energy lost by flow up the tubing
             and  through any surface pipes.  In the reservoir, the energy losses depend on
             the intrinsic permeability, the relative permeability to oil, and the kinematic
             viscosity of  the oil. In the well, the energy loss depends on the internal dia-
             meter and length of  the tubing, and also on the kinematic viscosity of  the oil.
               Within  the  reservoir,  there  is  now  a  potential  gradient towards the well
             from all  directions, and the oil flows radially  into the well - downdip from
             above the well, updip from below the well, and horizontally from along strike.
             Intuition is  not  always  reliable  in  these  matters,  so  we  must  examine the
             flow more carefully.
               When  a liquid  is at rest, the entire body of liquid is at constant potential,
             that is:

             Cf, = gh = g (- P + z) =  constant                               (8.12)
                        Pg

             so that the change of  pressure head to different levels is exactly equal to the
             change of  elevation. When the well is put onto production, the potential in
             the  well  is  made  less than  that in the reservoir, and a potential gradient is
             created down which the oil flows to the well.
               The potential is proportional to the total head of the oil in the reservoir:
                  P
                      +
             h,  = -  =  2681 - 2050 =  631 m.                                (8.13)
                       z
                 p0g
             So the energy of  the oil reservoir can be represented by a conceptual surface
             known as a potentiometric surface,  and while the oil is static, this surface is
             horizontal and  elevated  (in  our example) 631 m above the datum surface,
             taken here to be the level of  the well head. When a well is put onto produc-
             tion, a cone of depression is imposed on this surface (Fig. 8-14) and the equi-
            potential  lines  or contours on this surface form circles around the well (Fig.
            8-15). Flow in the reservoir is normal to the equipotential surfaces - normal
            to the equipotential lines in plan - that is, radial to the well. The better the
            effective permeability to oil, the shallower the cone of  depression.
              The  oil  flows  parallel  to the bed  surfaces, as it must, and normal to the
            equipotential surfaces that form concentric cylinders about the well. Ignoring
            compressibility, equal volumes of  oil cross any of  these concentric surfaces
            in unit time, so the oil is accelerating towards the well. Regarding the well as
            normal  to the reservoir for simplicity, the area of  any  concentric  surface is
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