Page 107 - Petroleum and Gas Field Processing

operating conditions:
Gas Specific gravity: 0.6

Oil gravity: 35 API
Operating pressure: 985 psi

Operating temperature: 60 F
Retention time: 3 min
C d : 1.1709

Solution
From Example 1, because we have the same operating conditions, the fluid
properties will be the same:

3:708 lb
g ¼ 3
ft
53:03 lb
o ¼ 3 and Z ¼ 0:84
ft
1. To determine the actual gas capacity of the separator: Determine
the separator effective length for gas capacity from Eq. (21):
D
L ¼ L þ
s
g
12
L g ¼ 14 ð12=36Þ¼ 14 3 ¼ 11 ft
Rearranging Eq. (14) to solve for Q g , we have

P g d m
1=2
o
Q ¼ 0:00237L D
g
g
TZ g C d
Substitute L g ¼ 11 and D ¼ 36 in the above equation and solve
for Q g :

1000
Q g ¼ 0:00237ð11 36Þ
520 0:84
1=2
53:03 3:708 100

53:03 1:1709
Q g ¼ 72:4 MMSCFD
2. To determine the actual oil capacity of the separator: Determine
the separator effective length for oil capacity from Eq. (22):
L o ¼ 34L s ¼ 3 414 ¼ 10:5ft

Copyright 2003 by Marcel Dekker, Inc. All Rights Reserved.