Page 135 - Phase Space Optics Fundamentals and Applications
P. 135

116   Chapter Four


                    A careful calculation for the case of   = 0 leads to
                                                 2
                                RW g (x 0 , 0) = |g(x 0 )| ∝ RW f (x 0 , 0)  (4.31)
                    while for the value   =  /2 the following result is obtained




                       RW g x  /2 ,  ∝ RW f x  /2 sin   ,   ,  tan   =−  f

                                 2
                                                                    (4.32)
                    Note that the effect of this propagation through a thin lens of
                    focal length f is also physically equivalent to the illumination of
                    the incident light distribution by a spherical wavefront whose
                    focus is located at a distance   = f from the input plane. Thus,
                    thesameresultsdiscussedherecanbeappliedstraightforwardly
                    to that case.
                  2. Free-space (Fresnel) propagation. If we consider now the Fresnel
                    approximation for the propagation of a transverse coherent light
                    distribution f (x) by a distance z, namely,

                                     +∞

                                                 i       2


                              g (x) =   f (x ) exp  (x − x)  dx     (4.33)
                                                  z
                                    −∞
                    the transformation matrix M is given by

                                              1  − z
                                       M F =                        (4.34)
                                              0   1
                    and, therefore, the transformed RWT can be calculated through
                    the expression

                          RW g (x   ,  ) ∝ RW f (x   ,   ),  tan   = tan   −  z,



                                        x
                              x   =            sin                  (4.35)

                                   sin   +  z cos
                    For the projection with   = 0, one obtains
                                         2
                        RW g (x 0 , 0) = |g(x 0 )| ∝ RW f (x   ,   ),  tan   =− z,



                                 x 0
                            x   =  sin                              (4.36)

                                  z
                    and for the orthogonal projection   =  /2 the following result
                    is achieved


                                 RW g x  /2 ,  ∝ RW f  x  /2 ,      (4.37)
                                           2              2
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