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Optical Fibers and Optical Fiber Amplifiers

          202   Advanced Topics

          around the central axis, and z the length of the fiber. The Laplacian
          operator has the following form in cylindrical coordinates:

                                 2   1      1    2      2
                           2
                            =     +       +        +                  (9.5)
                                r 2  r   r  r 2     2   z 2
            We can deal with the z dependence of the problem by substituting a
          trial solution for the z component that looks like a simple sinusoidal
          wave. That is,
                                 E(z, t) = Ae (j t–i	t)               (9.6)

          This leaves us with an equation in r and   that describes the behavior
          of the electric field in the circular cross section of the fiber:

                   2         1                       l 2
                                                 2
                                             2
                    E(r,  ) +       E(r,  ) + k – 	 –     E(r,  ) = 0  (9.7)
                  r 2         r   r                  r 2
          A similar equation can be written down for the magnetic field.
            Because the fiber has a circular cross section, the variable    is
          quantized following the same reasoning as that of de Broglie in Chap-
          ter 2. The number l can only be an integer indicating how many peri-
          ods of the wave are found when you complete a full circle around the
          fiber cross section.
            This equation has been solved by many people, and the solutions
          are Bessel functions. Bessel functions are specially designed to de-
          scribe waves constrained by circular geometries, like the vibrations of
          a drum, for instance. Although they do not appear on your calculator
          keyboard like the sine and cosine functions, they make life much easi-
          er for describing these kinds of situations. In the radial direction, they
          oscillate with declining amplitude. We will not solve the equation, be-
          cause what you would really like to know is not what the electric field
          looks like, but rather the relationship between k, 	, and l. This rela-
          tionship is determined by the boundary conditions.
            The boundary conditions are determined by conditions of continu-
          ity of the electric and magnetic fields at the interface between the
          core and the cladding where there is a discontinuity in the index of
          refraction. This leads to a somewhat tedious exercise in algebra, the
          chief benefit of which is to bring the core diameter of the fiber into
          the problem, for the discontinuity in the index of refraction occurs
          when r = d/2. An important parameter involves the ratio of the fiber
          core diameter to the wavelength of light. This is called the V param-
          eter:
                                d            2    d
                                          n 2
                                     1 –
                           V = 
              = 
   NA                (9.8)
                                          n 1

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