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6.1 The temperature equation                107

            where the first term q is the heat flux and the second term is heat transport by convection,
            and v i is the velocity of component i. Fourier’s law gives the heat flux

                                                  dT
                                           q =−λ                                (6.4)
                                                  dx
            as the product of the temperature gradient and the heat conductivity λ (see Section 2.12).
            Notice that the bulk heat conductivity is an average heat conductivity for all components in
            the system. The heat conductivity is often isotropic, but it can also be non-isotropic just like
            the permeability. The minus sign in Fourier’s law is needed because heat flows from “high”
            to “low” temperatures. Energy conservation  E 1 =  E 2 requires that expressions (6.1)
            and (6.2) are equal, and we get

                        ∂                ∂                 ∂    ∂T
                               φ i   i e i  +  φ i   i v i e i  −  λ  = S       (6.5)
                        ∂t              ∂x                ∂x    ∂x
                             i               i
            when both sides are divided by  t  x.The t- and x-differentiations in equation (6.5)are
            carried out inside the parentheses and terms cancel because of mass conservation of each
            component
                                     ∂         ∂
                                       (φ i   i ) +  (φ i   i v i ) = 0         (6.6)
                                    ∂t        ∂x
            (see section 3.18). Equation (6.5) then simplifies to


                                   ∂e i          ∂e i
                                                       ∂   ∂T
                               φ i   i  +  φ i   i v i  −  λ    = S.            (6.7)
                                   ∂t            ∂x   ∂x    ∂x
                             i           i
            The specific internal energy e i is a function of temperature and volume. Assuming that the
            volume is constant gives that
                                  ∂e i   ∂T         ∂e i   ∂T
                                     = c i    and      = c i                    (6.8)
                                  ∂t     ∂t         ∂x     ∂x
            where

                                                ∂e i
                                          c i =                                 (6.9)
                                                ∂T  V
            is the specific heat capacity at constant volume for component i. The rate of change of
            internal energy (6.8) gives that expression (6.7) for energy conversion becomes


                                  ∂T                 ∂T     ∂    ∂T
                           φ i   i c i  +   φ i   i c i v i  −  λ    = S.      (6.10)
                                  ∂t                 ∂x    ∂x    ∂x
                         i                i
            Although the temperature equation is derived in 1D it is straightforward to generalize it to
            3D. All we have to do is to replace ∂/∂x with the ∇-operator, and the temperature equation
            becomes
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