Page 194 - Physical chemistry understanding our chemical world
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THERMODYNAMICS AND THE EXTENT OF REACTION       161



                                     Justification Box 4.5

                Consider again the simple reaction of Equation (4.46):

                                          aA + bB = cC + dD
                We ascertain the Gibbs energy change for this reaction. We start by saying


                                    G =    νG (products) −  νG (reactants)
                where ν is the respective stoichiometric number; so

                                                                                (4.50)
                                    G = cG C + dG D − aG A − bG B
                                                                   O
                                                      O
                From an equation like Equation (4.43), G = G + RT ln(p/p ), so each G term in
                Equation (4.50) may be converted to a standard Gibbs function by inserting a term like
                Equation (4.43):

                                 O
                                                     O
                        G = cG + cRT ln     p C  + dG + dRT ln  p D  − aG  O
                                C                    D                   A
                                            p  O                p  O

                                      p A      O          p B
                             −aRT ln      − bG − bRT ln                         (4.51)
                                               B
                                      p  O                p  O
                We can combine the G  O  terms as  G  O  by saying
                                                        O
                                            O
                                                  O
                                      O
                                   G = cG + dG − aG − bG       O                (4.52)
                                            C     D     A     B
                So Equation (4.51) simplifies to become:

                                           p C           p D           p A
                                O
                        G =  G + cRT ln        + dRT ln      − aRT ln
                                           p  O          p  O          p  O

                                      p B
                            − bRT ln                                            (4.53)
                                      p  O
                  Then, using the laws of logarithms, we can simplify further:
                                                       O c     O d
                                                  (p C /p ) (p D /p )
                                        O
                                G =  G + RT ln                                  (4.54)
                                                               O b
                                                       O a
                                                  (p A /p ) (p B /p )
                  The bracketed term is the reaction quotient, expressed
                in terms of pressures, allowing us to rewrite the equation  We changed the posi-
                in a less intimidating form of Equation (4.49):  tioned of each stoi-
                                                               chiometric number via
                                     O
                            G r =  G + RT ln Q                 the laws of logarithms,
                                     r
                                                                                 b
                                                               saying b × ln a = ln a .
                A similar proof may be used to derive an expression
                relating to  G  O  and K c .
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