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250    ACIDS AND BASES


                       Why do equimolar solutions of sulphuric acid
                       and nitric acid have different pHs?

                      Mono-, di- and tri-basic acids

                                      Nitric acid, HNO 3 , readily dissolves in water, where it dissociates
              Equimolar means ‘of     according to
              equal molarity’, so
                                                                       +
              equimolar solutions            HNO 3(aq) + H 2 O −−→ 1H 3 O (aq) + NO −      (6.27)
                                                                                3(aq)
              have the same concen-
              tration.                The stoichiometry illustrates how each formula unit generates a sin-
                                      gle solvated proton. By contrast, sulphuric acid, H 2 SO 4 , dissociates
                                      in solution according to

                                                                        +
                                             H 2 SO 4(aq) + 2H 2 O −−→ 2H 3 O (aq) + SO 2−  (6.28)
                                                                                 4(aq)
                      so each formula unit of sulphuric acid generates two solvated protons. In other words,
                      each mole of nitric acid generates only 1 mol of solvated protons but each mole of
                      sulphuric acid generates 2 mol of solvated protons. We say nitric acid is a mono-protic
                      acid and sulphuric acid is a di-protic acid. Tri-protic acids are rare. Fully protonated
                      ethylene diamine tetra-acetic acid H 4 EDTA (V) is a tetra-protic acid.


                                                   OH              O
                                              O
                                                                       OH
                                                   N   CH 2  CH 2  N
                                                                       O
                                            OH
                                                   O              OH
                                                         (V)

                        Equation (6.27) demonstrated how the concentration of the solvated protons equates
                      to the concentration of a mono-protic acid from which it derived; but, from Equation
                      (6.28), the concentration of the solvated protons will be twice the concentration if the
                      parent acid is di-protic. These different stoichiometries affect the pH, as demonstrated
                      now by Worked Examples 6.6 and 6.7.


                      Worked Example 6.6 Nitric acid of concentration 0.01 mol dm −3  is dissolved in water.
                      What is its pH?
                                                                                          +
                      Since one solvated proton is formed per molecule of acid, the concentration [H (aq) ]is
                                    −3
                      also 0.01 mol dm .
                        The pH of this acidic solution is obtained by inserting values into Equation (6.20):
                                                   pH =− log [0.01]
                                                             10
                                                   pH = 2
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