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                  ethylene glycol, and various sugars. For example, the glycerol concentration in larvae     Section 12.3
                  of the goldenrod gall moth is near zero in summer months but increases to 19% by  Freezing-Point Depression and
                                                                                                       Boiling-Point Elevation
                  weight in winter months. An alternative strategy used by many fish, insects, and plants
                  is to have antifreeze proteins keep their fluids in a metastable supercooled liquid state
                  (Sec. 7.4) from 1 to 10 K below the freezing point. The antifreeze proteins bind to the
                  surface of small ice crystals, preventing their growth.




                  EXAMPLE 12.1 Molecular weight from freezing-point
                                         depression

                     The molal freezing-point-depression constant of benzene is 5.07 K kg/mol. A
                     0.450% solution of monoclinic sulfur in benzene freezes 0.088 K below the freez-
                     ing point of pure benzene. Find the molecular formula of the sulfur in benzene.
                        The solution is very dilute, and we shall assume it to be ideally dilute.
                     100.000 g of solution contains 0.450 g of sulfur and 99.550 g of benzene. From
                      T   k m , the sulfur molality is
                       f
                             f
                               B
                                          ¢T f       0.088 K
                                  m                              0.0174 mol>kg
                                    B
                                           k f    5.07 K kg>mol
                     But m   n /w [Eq. (9.3)], so the number of moles of sulfur is
                          B
                               B
                                  A
                              n   m w   10.0174 mol>kg210.09955 kg2   0.00173 mol
                               B
                                       A
                                     B
                     The sulfur molar mass is
                                 M   w >n   10.450 g2>10.00173 mol2   260 g>mol
                                        B
                                  B
                                           B
                     The atomic weight of S is 32.06. Since 260/32.06   8.1   8, the molecular for-
                     mula is S .
                             8
                     Exercise
                     For D O (where D   H), the normal freezing point is 3.82°C and   H (T*)
                                       2
                          2
                                                                              fus
                                                                                    f
                                                                                 m
                     6305 J/mol. (a) Find k for D O. (b) Find the freezing point of a solution of
                                         f
                                               2
                     0.954 g of CH COCH in 68.40 g of D O. Explain why your answer is approx-
                                        3
                                 3
                                                      2
                     imate. [Answers: (a) 2.02 K kg/mol; (b) 3.33°C.]
                                          6
                      As a pure substance freezes at fixed pressure, the temperature of the system
                  remains constant until all the liquid has frozen. As a dilute solution of B in solvent A
                  freezes at fixed pressure, the freezing point keeps dropping, since as pure A freezes
                  out, the molality of B in the solution keeps increasing. To determine the freezing point
                  of a solution, one can use the method of cooling curves (Sec. 12.8).
                      Freezing points are usually measured with the system open to the air. The dis-
                  solved air slightly lowers the freezing points of both pure A and the solution, but the
                  depression due to the dissolved air will be virtually the same for pure A and for the
                  solution and will cancel in the calculation of  T .
                                                           f
                      If there are several species in solution, then x in (12.8) equals 1   
  x , where
                                                           A                    i A  i
                  the sum goes over all solute species. Equation (12.11) becomes ln g x    
  x .
                                                                            A A      i A  i
                  For a dilute solution, we have x   M m , and Eq. (12.15) becomes for several solute
                                             i    A  i
                  species
                               ¢T   k m    ideally dil. soln., pure A freezes out   (12.17)
                                        f
                                  f
                                          tot
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