Page 154 - Pipeline Rules of Thumb Handbook
P. 154

Hydrostatic Testing  141

           Volume required at test pressure


                                                                                            2
                                                                                       .
           V tp =  V ¥  F wp ¥  F pp ¥  F pwt              (2)   V = 0 0408  ¥ (10 75  -(2  ¥ 0 279 )) ¥ 5 280,  ¥ 5
                                                                     .
                                                                              .
                                                                   = 111 888  gallons
                                                                       ,
           V tp = Gallons contained in test section at test pressure P, and
           temperature T - °F.
                                                                 Volume required to achieve test pressure = V tp = V ¥ F wp ¥
                                                                 F pp ¥ F pwt .
           F wp = Factor to correct for the compressibility of water
           due to increasing pressure from 0psig to test pressure P,
           psig                                                  F wp = 1 1  - ( [ 4 5 10 -5 ) ¥ (2430 14 73.  )]
                                                                            .
                                                                              ¥
                                                                      .
                                                                    = 1 007479.
           F pp = Factor to correct for volume change in pipeline due to
           pressure increase from 0psig to test pressure P, psig
                                                                     1
                                                                 F pp =+ ( [ 10 75 0 279 ) ¥ (0 91 2430.  ¥  (30  ¥ 10 6 ))]
                                                                               .
                                                                           .
                                                                                    - )]
           F pwt = Factor to correct for the change in water volume and  +[3 6 10  -6  ¥ (50 60
                                                                          ¥
                                                                        .
           pipe volume due to change in pipe and water temperature  = 1 002804.
           from base of 60°F to pipe and water test temperature, T -
           °F.
                                                                 F pwt =  F pt  F wt
                      .
                        ¥
                                    .
               1
           F wp = [1  -(4 5 10 -5 ) ¥  P ( 14 73 )]        (3)
                                                                             6
                                                                     1
                                                                 F pt =+ ( [ 50  - ) ¥ 18 2 10 -6 ]
                                                                                     ¥
                                                                                   .
                                                                              0
           P = Test pressure, psig.
                                                                      .
                                                                    = 0 999818
           F pp =+ ( [  D t) ¥ (0 91 30 10 6 )]
                          .
                                 ¥
                             P
               1
                                                                 F wt = 0 9993061 ( from Table ) 1
                                                                      .
                             60
                    ¥
               +[3 6 10 -6 ( T - )]                        (4)
                  .
                                                                               .
                                                                       .
           D = Outside diameter of pipe, inches.                 F pwt = 0 999818 0 9993061
            t = Pipe wall thickness, inches.                        = 1 000512
                                                                       .
           T = Pipe temperature, °F.
                                                                                                 .
                                                                        ,
                                                                            ¥
                                                                 V tp = 111 888 1 007457 1 002804 1 000512
                                                                                      ¥
                                                                                               ¥
                                                                               .
                                                                                        .
           F pwt =  F pt  F wt                             (5)
                                                                        ,
                                                                    = 113 099  gals.
           F pt = Factor to correct for change in pipe volume due
           to thermal expansion of the pipe from base temperature of  Incremental volume required to reach test pressure, P.
           60°F.
           F pt =+ ( [  T - ) ¥ 18 2 10 -6 ]               (6)      = 113,099 - 111,888 = 1,211gals.
                       0
                      6
               1
                            .
                              ¥
           F wt = Factor to correct for thermal change in specific   After a period of time, the test pressure, P has decreased
           water volume from 60°F to test water temperature. Refer to  to 2,418psig and the temperature of the pipe and test
           Table 1.                                              water has decreased to 48°F. The calculation procedure
                                                                 previously described may be repeated to determine if
           Sample calculation:                                   the pressure decrease is attributable to the decrease in
                                                                 temperature.
           Pipe Size:  10.750≤OD ¥ 0.279≤w.t. X-52
           Length:     5 miles                                   V   = 111,888gals.
           Test pressure: 2,430psig
                                                                 P 1  = 2,422psig
           Temperature: 50°F
                                                                 T 1  = 48°F.
                                                                 F wp1 = 1.007454
           Use equation 1 to determine the initial line fill volume, V.  F pp1 = 1.002796
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