Page 328 - Pipelines and Risers
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Risk Anabsis applied to Subsea Pipeline Engineering                   301


        Two flowlines and one umbilical are assumed for each template. The probability calculated
        considers a hit on any of these three items, for simplicity it is modeled as a total hit area of  3
        x(one generalized spool length)x(a lm corridor around each item).


        The assessment is based on objects being dropped through the moon  pool  of  the drill rig.
        Although objects may be dropped from the cranes, drops through the moon pool are assumed
        to be the worst case, as these will normally happen closest to the spools.
        A drill rig will be present on the field for the whole lifetime of the field (20yrs). A total of  17
        templates has been assumed. This means that the time spent on one template will be 20yrd17
        = 425 days. 75 days is added to this to account for increased drilling activities in the pre- and
        early production phase,  after the  lines are installed, giving a total  of  500 days of  drilling
        operations. There will be an  average of 20 liftdday during these 500 days, giving a total  of
        10000 liftsl20 years.
        Table 16.9 Basic Data and Assumptions.

                           Item                   Unit           Value
                         Water dwth                m           I   300
                II       Cone angle     I          0


                        Rig activity:      rig daydtemplate/20 years   500
                                            Number of liftdrig day   20
                         Design life              Years            20
                    Pipeline Outside Diameter     mm              259.8
                     Pipeline Wall thickness      mm              15.6


        16.9.4  Results

        Probabilities
        Cone radii are found using simple geometric principles.
             Cone radius, end spools: (302 + 3O2)In = 42
            Cone radius, end rockdump: (1302  + 3O2)In = 133
            X= 300 m . tan30 = 173.2 m
            From Equation 16.6 and Table of the standard normal distribution:
                 o = W2.575 = 67.2 m (In a normal distribution; P(-2.575ut<2.575) = 0.99)
             The cone area of the cone section encompassing the spools is:
                 A,  = n . (42)2 = 5542 m2
            The spool area within this cone area is:
                 Af = 60m -  3 . 1 m = 180 m2 (length of pipe & umbilical within A,  with  a  lm
                 corridor)
             Probability of hit within A,:
                 42 d67.2 m = 0.625 *P(-0.625<x<0.625)  = 0.468
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