Page 259 - Plant design and economics for chemical engineers
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                                            INTEREST AND INVESTMENT COSTS  229
         value at the end of the useful life will be $2000. The depreciation will be charged
         as a wst by making equal charges each year, the first payment being made at the
         end of the first year. The depreciation fund will be accumulated at an annual
         interest rate of 6 percent. At the end of the life period, enough money must have
         been accumulated to account for the decrease in equipment value. Determine the
         yearly  cost  due to depreciation under these conditions.
          (NOTE: This method  for  determining depreciation  k  based on an ordinary annuity
        and  iv  known as the sinking-fund   method.)

         Solution. This problem is a typical case of an ordinary annuity. Over a period of 10
        years, equal payments must be made each year at an interest rate of 6 percent.
         After 10 years, the amount of the annuity must be equal to the total amount of
         depreciation.

             Amount of annuity = S
             Total amount of depreciation = $12,000 -  $2000 = $10,000 = S
             Equal payments per year = R = yearly cost  due to depreciation
             Number of payments = n =  10
             Annual interest rate = i = 0.06.

        From Eq. (21),
                                              0.06
                  R =  S  (1  +  iin   _  1 =  $10,~   ~l.M~lo   _  1 =  $759/year


        Yearly cost due to depreciation = $759
        Example 6  Application of annuities in determining amount of depreciation with
        continuous cash flow and interest compounding. Repeat Example 5 with contin-
        uous cash flow and nominal annual interest of 6 percent compounded  wntin-
        uously.


        Solution. This problem is solved in exactly the same manner as Example 5, except
        the appropriate Eq. (23) for the continuous-interest case is used in place of the
        discrete-interest  equation.

             Amount of annuity = S
             Total amount of depreciation = $12,000 -  $2000 = S
             Equal payments per year based on continuous cash  flow  and interest
             compounding = E  = yearly cost  due to depreciation
             Number of years = n  = 10
             Nominal interest rate with continuous compounding = r = 0.06

        From Eq. (231,
                                            0.06
                    K=s+                           =  %730/year
                         e      =  $10~meco.06xlo,    =  1
        Yearly  cost  due to depreciation = $730
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