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228  PLANT DESIGN AND ECONOMICS FOR CHEMICAL ENGIN  ERS
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      periods in n  years is mn.  With m  annuity payments per year, let R  represent
      the total of all ordinary annuity payments occurring regularly and uniformly
      throughout the year so that R/m  is the uniform annuity payment at the end of
      each period. Under these conditions, Eq. (21) becomes
                          s  = i? [ 1 + (  ,/m)](m’rXm)   -  1
                              -                                         (22)
                               m          r/m
           For the case of continuous cash flow and interest compounding, m
      approaches infinity, and Eq.  (22),  by use of Eq.  (10,  becomes?

                                                                        (23)


      Present Worth of an Annuity

      The present worth of un  annuity is defined as the principal which would have to
      be invested at the present time at compound interest rate  i  to yield a total
      amount at the end of the annuity term equal to the amount of the annuity. Let
      P  represent the present worth of an ordinary annuity. Combining Eq. (5) with
      Eq. (21) gives, for the case of discrete interest compounding,
                                p = R (1 + 9” - 1                       (3
                                        i(1  + i)”
           The expression  [Cl  +  i)”  -  l]/[i(l  +  i)“]  is referred to as the  discrete
      uniform-series present-worth factor or the  series present-worth factor, while the
      reciprocal  [i(l + i)“]/[(l  + i)” - l]  is often called the capital-recovery factor.
           For the case of continuous cash flow and interest compounding, combina-
      tion of Eqs. (12) and (23) gives the following equation which is analogous to Eq.
      (24):
                                         m  - 1
                                  p,RL                                  (25)
                                          rem
           Example 5  Application of annuities in determining amount of depreciation with
           discrete interest compounding.  A piece of equipment has an initial installed value
           of $12,000. It is estimated that its useful life period will be 10 years and its scrap



      tThe  same result is obtained from calculus by noting that the definition of  E is such that the
      differential change in S with n is equal to 8, which is the constant gradient during the year, plus
      the contribution due to interest, or  dS/dn   =  R  +  rS.  This expression can be integrated as follows to
      give Eq. (23):


                             R + rs             em - 1
                           In - =rn   o r  S=R   -                     P)
                               R               (   r  1
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