Page 176 - Plastics Engineering
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Mechanical Behaviour of  Plastics                               159

                  An  underground  polypropylene storage tank is  a  sphere of  diameter  1.4 m.  If  it  is  to  be
                designed to resist an external pressure of 20 kN/m2 for at least 3 years, estimate a suitable value
                for the wall thickness. Tensile creep data may be  used  and the density of  the polypropylene is
                904 kg/m3.
                  2.9  A polypropylene bar with a square section (10 mm x  10  mm) is 225  mm long. It is pinned
                at both ends and an axial compressive load of  140 N is applied. How long would it be before
                buckling would occur. The relationship between the buckling load, Fc, and the bar geometry is

                                             F,  = R=EI/L’
                where L is the length of the bar and I is the second moment of area of the cross-section.
                  2.10  Show that a ratio of depth to thickness equal to 10 is the nod limit if buckling is to be
                avoided during short-term loading of plastics. What is likely to happen to this ratio for long-term
                loading? You should consider the situation of buckling of a strut fixed at both ends for which the
                critical buckling load is given by
                                                 4n2EI
                                             P, = -
                                                   L2
                  2.11 Show that the critical buckling strain in a strut with pinned ends is dependent only  on
                the geometry of the strut.
                  A polypropylene rod, 150 mm long is to be designed so that it will buckle at a critical strain of
                0.5%. Calculate a suitable diameter for the rod and the compressive load which it could transmit
                for at least one year.
                  2.12  A circular polypropylene plate, 150 mm in diameter is simply supported around its edge
                and is subjected to a uniform pressure of 40 kN/m2. If the stress in the material is not to exceed
                6 MN/mz, estimate a suitable thickness for the plate and the deflection, 8, after one year.  The
                stress in the plate is given by
                                      u = 3(1 + v)PR2/8hZ
                and                   S  = [3(1 - v)(5 + v)Pp]/16Eh3
                  2.13  A cylindrical polypropylene bottle is used to store a liquid under pressure. It is designed
                with a 4 mm skirt around the base so that it will continue to stand upright when the base bulges
                under  pressure. If  the diameter of  the bottle is 64 mm and it has a uniform  wall thickness of
                2.5 mm,  estimate the maximum internal pressure which can be used  if  the container must not
                rock on  its base after one year. Calculate also the  diameter change which  would  occur in  the
                bottle after one year under pressure.
                  2.14  A  rectangular section polypropylene beam has a length, L  of  200 mm and a width  of
                 12 mm. It is subjected to a load, W, of  150 N uniformly distributed over its length, L, and it is
                simply supported at each end. If the maximum deflection of the beam is not to exceed 6 mm after
                a period of  1 year estimate a suitable depth for the beam. The central deflection of  the beam is
                given by
                                            6 = 5 WL/384EI
                  2.15  In a particular application a 1 m length of 80 mm diameter polypropylene pipe is subjected
                to two dimetrically opposite point loads.  If  the wall thickness of the pipe is 3 mm,  what is the
                maximum value of the load which can be applied if the change in diameter between the loads is
                not to exceed 3 mm in one year.
                  The deflection of  the pipe under the load is given by
                                          W
                                       6 = - [0.48(L/R)0.5(R/h)’.22]
                                          Eh
                and the stress is given by  D = 2.4  W/h2 where W is the applied load and h is the wall thickness
                of the pipe.
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