Page 97 - Plastics Engineering
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80                                    Mechanical Behaviour of Plastics

                         Buckling is complex to analyse but  if  we consider the rib as a flat plate,
                       clamped along one edge then Roark gives the formula for the critical buckling
                       stress as
                                                       1.2E       2                 (2.24)
                                                     (1 - 9)
                       or






                       If  we  take the  critical stress as the yield  stress then  for many  plastics, the
                       ratio of UJE is approximately 35 x   Using Poisson's ratio, u = 0.35 and
                       taking /I = 0.6, as before, then
                                                h
                                                _-   h D  - 0.267
                                                d-5'2-
                       or
                                                d        h
                                                - = 3.75  -
                                                D        D
                       This line may  be superimposed on the rib design data as shown in Fig. 2.28.
                       Combinations of dimensions above this line are likely to provide ribs which are
                       too slender and so are liable to buckling. Combinations below the line are likely
                       to be acceptable but do remember the assumptions made in the determination
                       of  the buckling line - in particular, the ratio of u,/E  will increase with time
                       due to creep and this will cause the buckling line to move downwards.
                         Returning  to  the  Example, it  is  apparent that  the  dimensions chosen lie
                       above the buckling line. It is necessary therefore, to choose other dimensions.
                       For example, h = 2.5 mm gives
                                        h             W
                                        - = 0.33,    - 0.66 (as before)
                                                         =
                                        D            ND
                       So d/D = 1.15 which gives d  = 11.15(7.6) = 8.7 mm.
                         These dimensions lie below the buckling line and  so are acceptable. The
                       solution would  therefore be  a ribbed beam  with five ribs, plate thickness =
                       2.5 mm, rib thickness = 1.5 mm and rib depth = 8.7 mm.
                         It should be noted that ribbed sections play an extremely important part in
                       the design of  plastic products. Not only do they reduce manufacturing times
                       (because they utilise thinner sections), but they also save material. It may easily
                       be shown in this case that the volume of  the ribbed beam is half  the volume
                       of the flat acetal beam and this will result in a substantial cost saving.
                         Fig. 2.29  shows a design chart for slightly thicker ribs (/I = 0.8) so as to
                       reduce the likelihood of rib buckling.
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