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               384 Examples, problems and exercises

                      12.  (i) Write an equation for the phasor voltage E s at the sending end of a lossless
                             cable, in terms of the voltage V r , power P r and reactive power Q r at the
                             receiving end, if the electrical length is y radians. Use this equation to derive
                             an expression for the reactance X required to make the no-load voltage at the
                             receiving end of a radial transmission cable equal to the sending-end voltage.
                         (ii) Using the theory of part (i) and any necessary development thereof, deter-
                             mine the values of four reactors equally spaced along a 500 kV, 80-km
                             symmetrical line such that the no-load voltage profile is substantially flat.
                             Of the four reactors, one is at the sending end and one at the receiving end,
                             and the synchronous machines at the two ends contribute no reactive power.
                             The line series inductive reactance is 0:60 
/km and shunt capacitive
                             susceptance is 50:0 mS/km.
                         (iii) What is the maximum voltage in the compensated line of part (b) at no-load,
                             and where does it occur?
                         (iv) What is the total combined reactive power of the four reactors at no-load
                             and rated voltage?

                                                               Z o
                          (i) E s ˆ V r cos y ‡ jZ o I r sin y ˆ V r cos y ‡  sin y
                                                               X
                             so that for E s ˆ V r
                                                           sin y
                                                  X ˆ Z o
                                                         1   cos y
                                     p               6
                         (ii) y ˆ 80    (0:60   50   10 ) ˆ 0:43818 radians ˆ 25:1
                                  p             6
                             Z 0 ˆ  (0:60/(50   10 )) ˆ 109:545
                         (iii) 2X at the ends and X at two intermediate locations (26.7 km from each end).









                      Fig. 9.7



                                      Z 0  sin (y/n)  109:545  sin (25:1/3)
                                  X ˆ               ˆ                     ˆ 748
                                       2 1   cos (y/n)  2    1   cos (25:1/3)

                             Maximum voltage is at the mid-point and at 80/6 ˆ 13:3 km from each end:
                             V m ˆ E s /cos (y/2n)  with  n ˆ 3;  i.e.  V m ˆ 500/ cos (25:1/6) ˆ 500
                             1:00267 kV line±line or 1.00267 p.u.
                                                               p
                                                                   2
                         (iv) Totalcompensatingreactivepower ˆ (500/ 3) /748 3  (1 ‡1‡1/2 ‡1/2) ˆ
                             1:003MVAr.
                      13. A 500-kV cable is 80 km long and has a mid-point dynamic shunt compensator
                         that maintains the voltage at its terminals equal to 1.0 p.u. under all loading
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