Page 206 - Probability and Statistical Inference
P. 206

4. Functions of Random Variables and Sampling Distribution  183

                           In (4.2.2), the multiplier n! arises because y , ..., y  can be arranged among
                                                                1
                                                                      n
                           themselves in n! ways and the pdf for any such single arrangement amounts
                           to             . Often we are specifically interested in the smallest and largest
                           order statistics. For the largest order statistic Y , one can find the distribution
                                                                  n
                           as follows:






                           and hence the pdf of Y  would be given by
                                              n



                           in the appropriate space for the Y values. In the same fashion, for the smallest
                           order statistic Y , we can write:
                                        1






                           and thus the pdf of Y  would be given by
                                             1



                           in the appropriate space for the Y values.
                                 In the Exercise 4.2.5, we have indicated how one can find the
                                   joint pdf of anY two order statistics Y  = X  and Y  = X .
                                                                   i   n:i   j   n:j
                              Using the Exercise 4.2.5, one can derive the joint pdf of Y  and Y . In order
                                                                                   n
                                                                             1
                           to write down the joint pdf of (Y , Y ) at a point (y , y ) quickly, we adopt the
                                                      1
                                                         n
                                                                     1
                                                                       n
                           following heuristic approach. Since y , y  are assumed fixed, each of the
                                                               n
                                                            1
                           remaining n – 2 order statistics can be anywhere between y  and y , while
                                                                                     n
                                                                               1
                           these could be any n – 2 of the original n random X’s. Now, P{y  < X  < y } =
                                                                                1
                                                                                        n
                                                                                     i
                           F(y ) – F(y ), for each i = 1, ..., n. Hence, with   the joint pdf of (Y ,
                                                                                          1
                              n
                                    1
                           Y ) would be given by:
                            n
   201   202   203   204   205   206   207   208   209   210   211