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9. Confidence Interval Estimation  461

                           Hence, we conclude that




                           is a (1 – α) two-sided confidence interval estimator for the variance ratio
                                 By taking the square root throughout, it follows immediately from
                           (9.3.11) that




                           is a (1 – α) two–sided confidence interval estimator for the ratio σ /σ . !
                                                                                    1  2









                              Example 9.3.5 Ratio of Negative Exponential Scales: Suppose that
                           the random variables X , ..., X  are iid having the common pdf f(x; µ ,
                                                      ini
                                                i1
                                                                                          i
                                                               –1
                           s ), n  ≥ 2, i = 1, 2, where f(x; µ, σ) = σ  exp{–(x – µ)/σ}I(x > µ). Also
                            i
                               i
                           let the  X ’s be independent of the  X ’s. Here we assume that all four
                                                            2j
                                   1j
                                                                  +
                           parameters are unknown and (µ , σ ) ∈ ℜ × ℜ , i = 1, 2. With fixed α ∈ (0,
                                                      i
                                                         i
                           1), we wish to construct a (1 – α) two–sided confidence interval for σ /
                                                                                          1
                           σ  based on the sufficient statistics for θ ( = (µ , µ , σ , σ )). We denote
                            2                                        1  2  1   2
                           for i = 1, 2 and consider the pivot
                           It is clear that U is distributed as F 2n1–2,2n2–2  since 2(n  – 1)W /σ  is distrib-
                                                                                l
                                                                         l
                                                                                  i
                           uted as                and these are also independent. As before, let us
                           denote the upper 100(α/2)% point of the  F 2n –2,2n  – 2  distribution by
                                                                         2
                                                                     1
                           F n –2,2n –2,α/2 . Thus, we can write P{F 2n –2,2n –2,1–α/2  < U < F 2n –2,2n –2,α/2 } =
                                 2
                             1
                           1 – α and hence claim that        1   2              1   2
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