Page 282 - Process Modelling and Simulation With Finite Element Methods
P. 282

Coupling Variables Revisited            269

         In Mesh mode, we  need  to  set the  symmetry boundaries as  1 4  2 3, which  is
         treated pairwise so that  1 and 4 are symmetry boundaries as are 2 and 3.  The
         combination  of  symmetry  boundaries  and  boundary  condition  coefficients
         achieves doubly periodic  boundary  conditions.  Upon  meshing,  417  elements
         with 772 nodes were created in the 2-D domain.

         The major action is the computation of the projection coupling variables. Select
         Add/Edit Coupling Variables from the Options Menu.

           AddIEdit Coupling Variables
           Projection add proj 1.  Source Geom 1, subdomain 1, Integrand: c; int ord 2
           Local mesh transformation (x t x, y t y)
           Destination Geom 1 bnd 2 Check “Active in this domain” box.
           Evaluation point (x t x)
           Projection add proj2.  Source Geom 1, subdomain 1, Integrand: c; int ord 2
           Local mesh transformation (x t y, y t x)
           Destination Geom 1 bnd 1 Check “Active in this domain” box.
           Evaluation point (x t x)
                  Amlv/OK
          Set the Solver Parameters on the Solve menu with output times [0:0.001:0.06]
         on the time stepping page.  Select Apply/OK and hit the Solve = button on the
          toolbar.  After about twenty seconds of overhead computation, the time stepping
         begins.  As the problem is linear, it does not take long per step.
          Computation of (7.14) follows as below for t=0.06:

            Post Mode
            Subdomain integration:  domain 1  c  (at any time)   11= 0.037702
            Boundary integration:  bnd 2   proj 1 *x/0.037702   12= 0.49325
            Boundary integration:  bnd 1  proj2*y/0.037702   13= 0.51522
            Boundary integration:  bnd 2   proj 1 *xA2/0.037702   I4= 0.31825
            Boundary integration:  bnd 1  proj2*yA2/0.037702   I5= 0.34188

          The latter two give s,=0.2738  and s,=0.2765,  nearly identical spread, but this is
          expected  given  the  nearly  diffused  final  state.  For  time  t=O.,  the  same
         contributions result in:

            Post Mode
            Boundary integration:  bnd 2   pr0.j l*x/0.037702   12= 0.39999
            Boundary integration:  bnd 1  pr42*y/0.037702   13= 0.60012
            Boundary integration:  bnd 2   proj 1 *xA2/0.037702   14= 0.165
            Boundary integration:  bnd  I   proj2*yA2/0.037702   I5= 0.36726
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