Page 112 - Reservoir Geomechanics

96 Reservoir geomechanics

a. 1250 b. 800
700
1000
600
s 3 = 145 s 3 = 80
s 3 = 125
s = 60
3
500
s = 105
s 1 (MPa) s = 65 3 s 1 (MPa) 400 s 3 = 20 = 40
3
750
s 3
s = 85
s 3 = 45 3 s 1 = s 2 s 3 (MPa) s 1 = s 2
500 s = 25
3 s 3 = 25 300
= 45
s 3
(MPa)
s = 65 s 3 (MPa)
3 200
3
3
250 Dunham dolomite s = 85 Solenhofen limestone s = 20
C 0 = 450 MPa s = 105 C 0 = 375 MPa s 3 = 40
3
m = 0.65 s = 125 100 m = 0.55 s = 60
i 3 i 3
Mean misfit = 56.0 MPa s = 145 Mean misfit = 37.1 MPa s 3 = 80
3
0 0
0 200 400 600 800 1000 1200 0 100 200 300 400 500 600 700 800
s (MPa) s (MPa)
2 2
c. 350 d. 350
300 300
s 3 = 40
250 250
s 3 = 50
s 3 = 30
s 1 (MPa) 200 s = 15 s = 20 s 1 (MPa) 200 s = 25
3
3
150 3 s 1 = s 2 150 s 1 = s 2
s = 8
3 s (MPa)
s 3 = 5 3
s = 5
100 3 100
s = 8
3
s = 15 Yuubari shale s 3 (MPa)
Shirahama sandstone 3
50 C 0 = 95 MPa s = 20 50 C 0 = 120 MPa s 3 = 25
3
s = 30 m = 0.5
m = 0.8 3 i s = 50
i s = 40 3
Mean misfit = 9.6 MPa 3 Mean misfit = 13.5 MPa
0 0
0 50 100 150 200 250 300 0 50 100 150 200 250 300
s (MPa) s (MPa)
2 2
e.
2000
1800
1600
s = 150
3
1400
s 1 (MPa) 1200 s 3 = 100
1000
800 s = 60
3
s 1 = s 2
600 = 30 s (MPa)
3
s 3
s = 0
3
400 KTB amphibolite s 3 = 30
s 3 = 0
C 0 = 300 MPa s = 60
3
200 m = 1.2 s = 100
i 3
Mean misfit = 77.9 MPa s 3 = 150
0
0 500 1000 1500
s (MPa)
2
Figure 4.8. Best-fitting solution for all the rocks using the Mohr–Coulomb criterion. (a) Dunham
dolomite. (b) Solenhofen limestone. (c) Shirahama sandstone. (d) Yuubari shale. (e) KTB
amphibolite. After Colmenares and Zoback (2002). Reprinted with permission of Elsevier.