Page 203 - Rock Mechanics For Underground Mining
P. 203

THE FINITE ELEMENT METHOD

                                        The components of [N], i.e. the terms N i , are prescribed functions of position, and
                                          e
                                        [u ] is a column vector listing the nodal displacements u xi , u yi , u xj . . . etc.
                                          The interpolation functions which constitute the elements of [N] must be chosen
                                        to return the nodal displacements at each of the nodes. This requires that

                                                                  [N i ] xi,yi = [I]
                                                                  [N i ] xi,yj = [0], etc.
                                        where [I] and [0] are the identity and null matrices respectively. Also, since both
                                        components of displacement at a point are to be interpolated in the same way, it is
                                        clear that
                                                                    [N i ] = N i [I]

                                        where N i is a scalar function of position within the element.
                                          A simple development of a linear interpolation function is demonstrated by repre-
                                        senting the displacements in terms of linear functions of position, i.e.

                                                                u x =   1 +   2 x +   3 y
                                                                                                      (6.37)
                                                                u y =   4 +   5 x +   6 y
                                        The six interpolation constants are determined by ensuring that the displacements
                                        u x , u y assume the nodal values when nodal co-ordinates are inserted in equation
                                        6.37. Thus   1 ,   2 ,   3 are determined by solving the simultaneous equations

                                                                u xi =   1 +   2 x i +   3 y i
                                                                u xj =   1 +   2 x j +   3 y j
                                                                u xk =   1 +   2 x k +   3 y k

                                        Solution for   1 ,   2 ,   3 and some rearrangement, produces
                                               1
                                          u x =  [(a i + b i x + c i y)u xi + (a j + b j x + c j y)u xj + (a k + b k x + c k y)u xk ]
                                               2
                                                                                                      (6.38)

                                        where

                                                                  a i = x j y k − x k y j
                                                                  b i = y j − y k
                                                                   c i = x k − x j

                                        with cyclic permutation of i, j, k to obtain a j , etc., and

                                                         2  = 2 × area of the triangular element
                                                                ⎡         ⎤
                                                                 1   x i  y i
                                                             = 2 1   x j  y j  ⎦
                                                                ⎣
                                                                 1   x k  y k
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