Page 92 - Rotating Machinery Pratical Solutions to Unbalance and Misalignment
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Rotating Machinery: Practical Solutions

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                                                 90

                                      e

                                     b
                                           b     r
                                        Y
                                           c
                                                 a   ▲
                                               X

                        Figure 5-17. Determining the Vector Angle

            Example (5.4) (Cont’d)

            Step 4. Calculate the following additional vectors from the mea-
            sured values. First, the measured values will be assigned new
            names.
            A = N0 > N1      =  6.3 mils @ 198 degrees.
            Aa = F0 > F1     =  2.1 mils @ 7 degrees.
            B = F0 > F2      =  7.1 mils @ 121 degrees.
            Bb = N0 > N2  =  3.3 mils @ 281 degrees.
                 The following calculations are now performed:

               a   =  (Aa/A) mils @ (Aa – A) degrees = (2.1/6.3) @ (7 – 198)
                   degrees.
               a   =  .3 mils @ 171 degrees.

               b   =  (Bb/B) mils @ (Bb – B) degrees = (3.3/7.1) @ (281 – 121)
                   degrees.

               b   =  .5 mils @ 160 degrees.
              Na  = (N0 × a) mils @ (N0 + a) degrees = (7.1 × .3) mils @ (60
                   + 171) degrees.

              Na  =  2.1 mils @ 231 degrees.
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