Page 347 - Satellite Communications, Fourth Edition
P. 347

Error Control Coding  327

                                                                                      (00)
                                                                          (00)       0 0  0
                                  Key
                                                                         0 0  0       (11)
                                     (U1 U2)                                         1 0  0
                                                              (00)
                                     S1 S2  S3
                                                             0 0  0
                                                                                      (01)
                                                                          (11)       0 1  0
                                                                         1 0  0       (10)
                                                  (00)                               1 1  0
                                                 0 0  0
                                                                                      (11)
                                                                          (01)       0 0  1
                                                                         0 1  0       (00)
                                                              (11)                   1 0  1
                                                             1 0  0
                                                                                      (10)
                                                                          (10)       0 1  1
                                                                         1 1  0       (01)
                                       (00)                                          1 1  1
                              Data   0 0  0
                               in
                                                                                      (00)
                                                                          (11)       0 0  0
                                                                         0 0  1       (11)
                                                                                     1 0  0
                                                              (01)
                                                             0 1  0
                                                                                      (01)
                                                                          (00)       0 1  0
                                                                         1 0  1       (10)
                                                                                     1 1  0
                                                  (11)
                                                 1 0  0
                                                                                      (11)
                                                                          (10)       0 0  1
                                                                         0 1  1       (00)
                                                              (10)                   1 0  1
                                                             1 1  0
                                                                                      (10)
                                                                          (01)       0 1  1
                                                                         1 1  1       (01)
                                                                                     1 1  1
                              Figure 11.3 The tree diagram for the rate 1/2 convolutional encoder.
                              intended, it takes the lower branch, and then it can match all the fol-
                              lowing pairs with the branches in the decoding tree. On the basis of max-
                              imum likelihood, this would be the preferred path, and the correct input
                              1001 would be deduced.
   342   343   344   345   346   347   348   349   350   351   352