Page 127 - Schaum's Outline of Theory and Problems of Advanced Calculus
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118                            PARTIAL DERIVATIVES                         [CHAP. 6




















                                                           Fig. 6-3


                     LIMITS
                        Let f ðx; yÞ be defined in a deleted   neighborhood of ðx 0 ; y 0 Þ [i.e.; f ðx; yÞ may be undefined at
                     ðx 0 ; y 0 Þ].  We say that l is the limit of f ðx; yÞ as x approaches x 0 and y approaches y 0 [or ðx; yÞ
                     approaches ðx 0 ; y 0 Þ] and write lim f ðx; yÞ¼ l [or  lim  f ðx; yÞ¼ l]if for any positive number   we
                                             x!x 0
                                                            ðx;yÞ!ðx 0 ;y 0 Þ
                                              y!y 0
                     can find some positive number   [depending on   and ðx 0 ; y 0 Þ,in general] such that j f ðx; yÞ  lj <
                     whenever 0 < jx   x 0 j <  and 0 < j y   y 0 j < .
                                                                                         2
                                                                                                   2
                        If desired we can use the deleted circular neighborhood open ball 0 < ðx   x 0 Þ þð y   y 0 Þ <  2
                     instead of the deleted rectangular neighborhood.

                                          3xy
                     EXAMPLE.  Let f ðx; yÞ¼  if ðx; yÞ 6¼ð1; 2Þ  .As x ! 1 and y ! 2[or ðx; yÞ!ð1; 2Þ], f ðx; yÞ gets closer to
                                          0   if ðx; yÞ¼ ð1; 2Þ
                     3ð1Þð2Þ¼ 6 and we suspect that lim f ðx; yÞ¼ 6. To prove this we must show that the above definition of limit with
                                            x!1
                                            y!2
                     l ¼ 6issatisfied.  Such a proof can be supplied by a method similar to that of Problem 6.4.
                        Note that lim f ðx; yÞ 6¼ f ð1; 2Þ since f ð1; 2Þ¼ 0. The limit would in fact be 6 even if f ðx; yÞ were not defined at
                                x!1
                                y!2
                     ð1; 2Þ. Thus the existence of the limit of f ðx; yÞ as ðx; yÞ! ðx 0 ; y 0 Þ is in no way dependent on the existence of a value
                     of f ðx; yÞ at ðx 0 ; y 0 Þ.
                        Note that in order for  lim  f ðx; yÞ to exist, it must have the same value regardless of the
                                            ðx;yÞ!ðx 0 ;y 0 Þ
                     approach of ðx; yÞ to ðx 0 ; y 0 Þ.  It follows that if two different approaches give different values, the
                     limit cannot exist (see Problem 6.7). This implies, as in the case of functions of one variable, that if a
                     limit exists it is unique.
                        The concept of one-sided limits for functions of one variable is easily extended to functions of more
                     than one variable.


                                       1
                                                        1
                     EXAMPLE 1.  lim tan ð y=xÞ¼  =2, lim tan ð y=xÞ¼  =2.
                                 x!0þ            x!0
                                 y!1              y!1
                                       1
                     EXAMPLE 2. lim tan ð y=xÞ does not exist, as is clear from the fact that the two different approaches of Example
                                 x!0
                                 y!1
                     1give different results.
                        In general the theorems on limits, concepts of infinity, etc., for functions of one variable (see Page
                     21) apply as well, with appropriate modifications, to functions of two or more variables.
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