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                 172    Mechanical Engineering Design



                       EXAMPLE 4–12       The cantilevered hook shown in Fig. 4–13a is formed from a round steel wire with a
                                          diameter of 2 mm. The hook dimensions are l = 40 and R = 50 mm. A force P of 1 N
                                          is applied at point C. Use Castigliano’s theorem to estimate the deflection at point D at
                                          the tip.
                                Solution  Since  l/d and  R/d are significantly greater than 10, only the contributions due
                                          to bending will be considered. To obtain the vertical deflection at  D, a fictitious
                                          force Q will be applied there. Free-body diagrams are shown in Figs. 4–13b, c, and
                                          d, with breaks in sections  AB,  BC, and  CD, respectively.  The normal and shear
                                          forces, N and V respectively, are shown but are considered negligible in the deflec-
                                          tion analysis.
                                              For section AB, with the variable of integration x defined as shown in Fig. 4–13b,
                                          summing moments about the break gives an equation for the moment in section AB,

                                                                M AB = P(R + x) + Q(2R + x)                   (1)

                                                                    ∂M AB /∂Q = 2R + x                        (2)

                                          Since the derivative with respect to Q has been taken, we can set Q equal to zero. From
                                          Eq. (4–31), inserting Eqs. (1) and (2),


                                                            l                          l
                                                             1       ∂M AB        1
                                                 (δ D ) AB =     M AB       dx =       P(R + x)(2R + x)dx
                                                          0 EI        ∂Q         EI  0
                                                                                                              (3)
                                                          P     l  2         2      P     2   3  2   1  3
                                                       =       (2R + 3Rx + x )dx =    (2R l + l R + l )
                                                          EI  0                     EI        2      3



                  Figure 4–13                                   l
                                                                                            D
                                                           A      B
                                                                                    R
                                                                                P




                                                                               C
                                                                               (a)

                                                                  Q                       Q              Q
                                          V AB  x
                                                                   D                      D               D
                                              B              R                      R
                                          M                              V
                                           AB                         N   BC
                                                         P             BC       P                 V CD
                                                                      M
                                                                        BC                             M
                                                                                                   N CD  CD
                                                        C                      C
                                                        (b)                    (c)                    (d)
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