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                 394    Mechanical Engineering Design
                  Figure 7–18

                  Typical uses for retaining rings.
                  (a) External ring and (b) its
                  application; (c) internal ring
                  and (d) its application.



                                                                                                       Retaining ring
                                                          Retaining ring

                                             (a)                 (b)            (c)                 (d)

                                          of d/10 from the start of the shoulder fillet will prevent the two stress concentrations
                                          from combining with each other. 9
                                          Retaining Rings
                                          A retaining ring is frequently used instead of a shaft shoulder or a sleeve to axially posi-
                                          tion a component on a shaft or in a housing bore. As shown in Fig. 7–18, a groove is
                                          cut in the shaft or bore to receive the spring retainer. For sizes, dimensions, and axial
                                          load ratings, the manufacturers’ catalogs should be consulted.
                                              Appendix Tables A–15–16 and A–15–17 give values for stress-concentration fac-
                                          tors for flat-bottomed grooves in shafts, suitable for retaining rings. For the rings to seat
                                          nicely in the bottom of the groove, and support axial loads against the sides of the
                                          groove, the radius in the bottom of the groove must be reasonably sharp, typically about
                                          one-tenth of the groove width.  This causes comparatively high values for stress-
                                          concentration factors, around 5 for bending and axial, and 3 for torsion. Care should be
                                          taken in using retaining rings, particularly in locations with high bending stresses.




                        EXAMPLE 7–6       A UNS G10350 steel shaft, heat-treated to a minimum yield strength of 75 kpsi, has a
                                          diameter of 1  7  in. The shaft rotates at 600 rev/min and transmits 40 hp through a gear.
                                                     16
                                          Select an appropriate key for the gear.
                                            3
                                Solution  A  -in square key is selected, UNS G10200 cold-drawn steel being used. The design
                                            8
                                          will be based on a yield strength of 65 kpsi. A factor of safety of 2.80 will be employed
                                          in the absence of exact information about the nature of the load.
                         t
                   a                          The torque is obtained from the horsepower equation
                                F
                 F                                             63 025H   (63 025)(40)
                                                           T =         =            = 4200 lbf · in
                             b                                    n          600
                                          From Fig. 7–19, the force F at the surface of the shaft is
                            r
                                                                     T     4200
                                                                F =    =         = 5850 lbf
                                                                     r   1.4375/2
                                          By the distortion-energy theory, the shear strength is
                  Figure 7–19
                                                            S sy = 0.577S y = (0.577)(65) = 37.5 kpsi

                                          9 Ibid, p. 381.
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