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                 520   Mechanical Engineering Design
                                          effect of the direct shear. Thus, using Eq. (10–5) with Eq. (10–3), the curvature cor-
                                          rection factor is found to be
                                                                     K B     2C(4C + 2)
                                                                K c =   =                                  (10–6)
                                                                     K s   (4C − 3)(2C + 1)
                                          Now, K s , K B or K W , and K c are simply stress-correction factors applied multiplica-
                                          tively to Tr/J at the critical location to estimate a particular stress. There is no stress-
                                          concentration factor. In this book we will use
                                                                              8FD
                                                                       τ = K B                             (10–7)
                                                                              πd 3
                                          to predict the largest shear stress.
                                10–3      Deflection of Helical Springs

                                          The deflection-force relations are quite easily obtained by using Castigliano’s theorem.
                                          The total strain energy for a helical spring is composed of a torsional component and
                                          a shear component. From Eqs. (4–18) and (4–20), p. 162, the strain energy is
                                                                           2
                                                                                  2
                                                                          T l    F l
                                                                     U =      +                               (a)
                                                                         2GJ    2AG
                                                                                              2
                                                                               4
                                          Substituting T = FD/2, l = π DN,  J = πd /32, and  A = πd /4 results in
                                                                                   2
                                                                         2
                                                                           3
                                                                      4F D N     2F DN
                                                                  U =         +                               (b)
                                                                                   2
                                                                         4
                                                                        d G       d G
                                          where N = N a = number of active coils. Then using Castigliano’s theorem, Eq. (4–26),
                                          p. 165, to find total deflection y gives
                                                                              3
                                                                    ∂U    8FD N    4FDN
                                                                y =    =         +                            (c)
                                                                                     2
                                                                            4
                                                                    ∂F     d G      d G
                                          Since C = D/d, Eq. (c) can be rearranged to yield
                                                                                         3
                                                                     3
                                                                 8FD N        1     . 8FD N
                                                             y =          1 +      =                       (10–8)
                                                                                        4
                                                                    4
                                                                   d G       2C 2      d G
                                          The spring rate, also called the scale of the spring, is k = F/y, and so
                                                                              4
                                                                          .  d G
                                                                        k =                                (10–9)
                                                                              3
                                                                            8D N
                                10–4      Compression Springs
                                          The four types of ends generally used for compression springs are illustrated in Fig. 10–2.
                                          A spring with plain ends has a noninterrupted helicoid; the ends are the same as if a
                                          long spring had been cut into sections. A spring with plain ends that are squared or
                                          closed is obtained by deforming the ends to a zero-degree helix angle. Springs should
                                          always be both squared and ground for important applications, because a better transfer
                                          of the load is obtained.
                                              Table 10–1 shows how the type of end used affects the number of coils and the
                                                     3
                                          spring length. Note that the digits 0, 1, 2, and 3 appearing in Table 10–1 are often
                                          3 For a thorough discussion and development of these relations, see Cyril Samónov, “Computer-Aided
                                          Design of Helical Compression Springs,” ASME paper No. 80-DET-69, 1980.
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