Page 30 - Statistics and Data Analysis in Geology
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Elementary  Statistics



























                                               Number of discoveries
              Figure 2-3. Discrete distribution giving the probability of making n discoveries in a five-hole
                   drilling program when the success ratio (probability of a discovery)  is 10%.

              exploration company is determined to discover two new fields in a virgin basin it
             is prospecting, and will drill as many holes as required to achieve its goal. We  can
             investigate the probability that it will require 2,3,4,. . ., up to n exploratory holes
             before two discoveries are made.  The same conditions that govern the binomial
              distribution may be assumed, except that the number of  “trials”  is not fixed.
                  The probability distribution that governs such an experiment is called the neg-
              ative binomial, and its development is very similar to that of the binomial distribu-
              tion. As in that example, p is the probability of  a discovery and Y is the number of
              “successes” or discovery wells.  However, n, the number of  trials, is not specified.
              Instead, we wish to find the probability that x  dry holes will be drilled before Y
              discoveries are made. The negative binomial has the form




              Note the similarity between this equation and Equation (2.3); the term r + x - 1 ap-
              pears because the last hole drilled in a sequence must be the rth success. Expanding
              Equation (2.4) gives
                                           (Y fX - l)!
                                       P=             (1 - pIXpY
                                            (Y - l)!x!

                  If  the regional success ratio is assumed to be lo%, the probability that a two-
              hole exploration program will meet the company’s goal of  two discoveries can be
              calculated:              (2 + 0 - l)!
                                   P=             *  (1 - 0.1O)O . o.102
                                        (2 - l)!O!
                                     --.    o.90°  o.102
                                        l!
                                     -
                                       1!0!
                                     = 1 ’ 1 *  0.01 = 0.01
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