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L1592_Frame_C10  Page 93  Tuesday, December 18, 2001  1:46 PM









                        In the example, we used a standard deviation of 0.15 pH units for pH s . Let us apply the same error
                       propagation technique to see whether this was reasonable. To keep the calculations simple, assume that A,
                       K s , K 2 , and µ are known exactly (in reality, they are not). Then:

                                                                          −2
                                                        2
                                                            −2
                                         Var(pH s ) = (log 10 e) {[Ca] Var[Ca] + [Alk]  Var[Alk]}
                       The variance of pH s  depends on the level of the calcium and alkalinity as well as on their variances.
                        Assuming [Ca] = 36 mg/L, σ [Ca]  = 3 mg/L, [Alk] = 50 mg/L, and σ [Alk]  = 3 mg/L gives:

                                                                         2
                                                                      −2
                                                             −2
                                                                2
                                           Var(pH s ) = 0.1886{[36] (3)  + [50] (3) } = 0.002
                       which converts to a standard deviation of 0.045, much smaller than the value used in the earlier example.
                       Using this estimate of Var(pH s ) gives approximate 95% confidence intervals of:

                                                       0.03 < LSI < 0.47
                                                       6.23 < RSI < 6.77


                       This example shows how errors that seem large do not always propagate into large errors in calculated
                       values. But the reverse is also true. Our intuition is not very reliable for nonlinear functions, and it is
                       useless when several equations are used. Whether the error is magnified or suppressed in the calculation
                       depends on the function and on the level of the variables. That is, the final error is not solely a function
                       of the measurement error.




                       Random and Systematic Errors

                       The titration example oversimplifies the accumulation of random errors in titrations. It is worth a more
                       complete examination in order to clarify what is meant by multiple sources of variation and additive
                       errors. Making a volumetric titration, as one does to measure alkalinity, involves a number of steps:

                          1.  Making up a standard solution of one of the reactants. This involves (a) weighing some solid
                             material, (b) transferring the solid material to a standard volumetric flask, (c) weighing the
                             bottle again to obtain by subtraction the weight of solid transferred, and (d) filling the flask
                             up to the mark with reagent-grade water.
                          2.  Transferring an aliquot of the standard material to a titration flask with the aid of a pipette.
                             This involves (a) filling the pipette to the appropriate mark, and (b) draining it in a specified
                             manner into the flask.
                          3.  Titrating the liquid in the flask with a solution of the other reactant, added from a burette. This
                             involves filling the burette and allowing the liquid in it to drain until the meniscus is at a constant
                             level, adding a few drops of indicator solution to the titration flask, reading the burette volume,
                             adding liquid to the titration flask from the burette a little at a time until the end point is adjudged
                             to have been reached, and measuring the final level of liquid in the burette.
                        The ASTM tolerances for grade A glassware are ±0.12 mL for a 250-mL flask, ±0.03 mL for a 25-mL
                       pipette, and ±0.05 mL for a 50-mL burette. If a piece of glassware is within the tolerance, but not exactly
                       the correct weight or volume, there will be a systematic error. Thus, if the flask has a volume of 248.9 mL,
                       this error will be reflected in the results of all the experiments done using this flask. Repetition will not
                       reveal the error. If different glassware is used in making measurements on different specimens, random
                       fluctuations in volume become a random error in the titration results.
                       © 2002 By CRC Press LLC
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