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206    TEMPORAL DISCRETISATION

            5.3.4  OMF30 time integration scheme

            The recursive formula for this scheme is as follows:

                                         f t
                              v 1 = v t + λh                                    (5.112)
                                         m
                                       h
                              x 1 = x t +  v 1
                                       2
                                               f 1
                              v 2 = v 1 + (1 − 2λ)h
                                               m
                                       h
                            x t+h = x 1 +  v 2
                                       2
                                         f t+h
                            v t+h = v 2 + λh
                                          m
                                  1    1  &     √       1      1
                                         3
                              λ =   −      36 + 2 326 +  #       √
                                  2    12               6  3  36 + 2 326


            5.3.5  OMF32 time integration scheme

            This is an eleven-stage, fourth order scheme. The recursive formula for this scheme is
            as follows:

                                                          f 1
                                               v 1 = v t + ϑh
                 x 1 = x t + ρh v t
                                                          m
                                                          f 2    3
                                               v 2 = v 1 + λh
                 x 2 = x 1 + θh v 1                          + ξh G 2
                                                          m
                                                                      f 3
                 x 3 = x 2 + (1 − 2(θ + ρ))(h/2)v 2  v 3 = v 2 + (1 − 2(λ + ϑ))h
                                                                      m
                                                          f 4    3
                                               v 4 = v 3 + λh
                 x 4 = x 3 + (1 − 2(θ + ρ))(h/2)v 3          + ξh G 4
                                                          m
                 x 5 = x 4 + θh v 4
                                                                                (5.113)
                                               f 5
                                v t+ t = v 4 + ϑh
                                               m     where :
                                r t+ t = r 5 + ρ t v t+ t
                               ρ = 0.6419108866816235 E − 01
                               θ = 0.1919807940455741 E + 00
                               ϑ = 0.1518179640276466 E + 00
                               λ = 0.2158369476787619 E + 00
                               ξ = 0.9628905212024874 E − 03
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