Page 703 - The Mechatronics Handbook
P. 703

0066_Frame_C23  Page 11  Wednesday, January 9, 2002  1:53 PM







































                       FIGURE 23.8  Illustration of the differentiation technique for Fourier series coefficient computation.

                       which can be written as
                                                              ∞
                                                      x″ t() =  ∑  β k e j2πkf t
                                                                      0
                                                             k=∞
                                                              –
                         Figure 23.8(c) shows the result of differentiating x(t). It is noted that if a signal is periodic, its derivatives
                       will also be periodic. This implies that β k  is the complex Fourier series coefficient of x″(t) and can be
                       computed from

                                                   β k =  1 ∫  T/2  x″ t()e  – j2πkf t  t d
                                                                      0
                                                        ---
                                                        T  – T/2
                       where
                                                         
                                                                         
                                                     A
                                            x″ t() =  2--- δ t +  T   2δ t() +  δ t –  T 
                                                                             ---
                                                             --- –
                                                     T      2             2 
                         Thus,
                                                           
                                                      A
                                                            -------------- =
                                              β k =  – 8------sin 2 πkTf 0  ( j2πf 0 k) c k
                                                                            2
                                                           
                                                     T  2     2 
                         That is,
                                                           2A
                                                     c k =   ----------, k odd
                                                           2 2
                                                         
                                                          π k
                                                         
                                                          0,   otherwise
                      ©2002 CRC Press LLC
   698   699   700   701   702   703   704   705   706   707   708