Page 293 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 293

280                             Vibration of Continuous Systems   Chap. 9

                                                                 Fundamental  n =]    f,=4cpm



                                                                 Mode  2  n =2

                                                                 Mode  3  n = 3   f,=  12cpm


                                                                 Mode  4  n = 4


                                                          Figure 9.4-4.
                              Example 9.4-2  Torsional Vibration
                                  On the day of the Tacoma Narrows Bridge collapse, it was reported that high winds of
                                  42  mph  had  excited  several  modes  of  vibration.  The  dominant  mode  was  moving
                                  vertically  with  a  node  at  midspan,  which  was  calculated  in  the  last  section.  This
                                  motion suddenly changed to torsional motion with a node  at midspan and a period of
                                  4 s, which  built  up  to large amplitudes of nearly 45°  before collapse.
                                       By referring to Sec.  9.3,  the  differential  equation  and  its solution  are
                                                                         d^e
                                                      { p l p d x ) ^   =  {IpGdx) ^
                                                                         J ?
                                                      /  ^P          pJp
                                       e {x , t )  =  yf sin wi/   jc  + B cos (  [C sin (ot   D cos cot]
                                                                     GIp
                                  where  the  term  Ip,  which was. canceled  in  Eq.  (9.3-3),  has been  retained  to  apply to
                                  this  problem.  We  recognize  here  that  the  term  pIp dx  is  the  mass  polar  moment  of
                                  inertia of the structure of length  dx,  and  the  term  I p G  dx  is the torsional  stiffness of
                                  length  dx, which was  shown  to be  equal  to  Tb^ =  19,900  X  10^  lb  •  ft^.
                                       The  equivalent  cross  section  of  the  bridge  for  the  polar  moment  of  inertia
                                  calculation  appears  in  Fig. 9.4-5.
                                                                  4320   (39)^
                                              J for the floor  = mh^/\2  =    -   17,000
                                                                   32.2   12
                                                                     955   / 39  2
                                           J for the girders plus cables  =  2  X   ^  ^   ^   |  ^  400
                                                        Total  J -   39,400 lb  •  s^







                                                                     Figure 9.4-5.
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