Page 346 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 346

Sec. 10.8   Generalized Force Proportional to Displacement     333


                                      For  il  =  0,  the  natural  frequencies  for the  single  element  analysis  arc
                                                            =  3.53


                                                          ia.  =  34.81
                                  For comparison,  the  exact values for  ii  =  0 arc

                                                          w,  =  3.515

                                                          ia.  =   22.032
                                  which  indicates  that  the  single-element  analysis  results  in  unacceptable  accuracy  for
                                  the  second  mode.  The  eigenvectors for the  single-element  analysis, which  are  deflec­
                                  tion  and  slope  at  the  free  end,  cannot  be  compared  to  the  more  conventional
                                  eigenvectors that  display deflection  along the  beam.
                              Example  10.8-4 Two-Element Beam
                                  If  we  divide  the  beam  into  two  equal  sections,  then  /  is  replaced  by  //2,  and  the
                                  rotational  force over the  second  clement  must be  changed to

                                                               ^        dx
                                  The  generalized  force  is  now
                                             Q  = mil}l  ^  I ^  ^   drdx

                                               = mil                        ‘PW',drdx\

                                  The  last  integral  in  this  expression  is  the  same  as  that  for  the  one-element  beam,
                                  except  for  /  replaced  by  1/2.  The  first  integral  now  needs  evaluating.  In  formulating
                                  the  equation of motion,  this  now requires changing all  /’s  in  the  matrices  to  1/2.
                                      We  now  suggest  a  different  approach  of  leaving  the  length  of  each  element
                                  equal  to  /,  so  that  the  total  length  of the  beam  is  21.  This  results  in  great  savings  in
                                  computation  because  the  matrices  for  each  clement  will  remain  the  same  as  that  for
                                  the  one-element  beam  and  all  the  /’s  inside  the  matrices  can  remain  as  /,  which  can
                                  be  assigned  as  unity  for  the  eigenvalue computation  as  before;  i.e., we  now  solve  the
                                  problem  shown  in  Fig.  10.8-3.  After  the  eigenvalues  arc  determined,  we  let  /  in  the
                                  expression  for the  eigenvalues be  replaced  by  y.




                                        F
                                        I           (2)         (3)

                                                    21-              Figure  10.8-3.
   341   342   343   344   345   346   347   348   349   350   351