Page 342 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
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Sec. 10.8   Generalized Force Proportional to Displacement     329


                              distributed  forces  normal  to  the beam,  and (2) for distributed  forces parallel  to  the
                              beam.
                                  Case  (1):  The  term  p(x)  in  the  virtual  work  equation  (10.7-2)  is  replaced  by
                             f(x)yix),  which  results  in  the  equation

                                                   ñW =  j ‘f{ x )y { x ) 5y( j )  dx    ( 10.8- 1)

                              With  y(x)  =    where   are  the beam  functions,  and  Qi  are  the  element  end
                              deflections  as  in  Eq.  (10.7-1),  the  virtual  work  is

                                                             dq, f'fi  X)   dx           ( 10.8-2)

                              and  the  generalized  force  becomes

                                                 e ,  =                                  (10.8-3)
                              which  is  proportional  to  the  displacement.
                              Example  10.8-1
                                  Figure  10.8-1  shows  a  cantilever  beam  with  clastic  foundation  under  the  outer  half of
                                  the  beam.  The  stiffness  of  the  foundation  is  - k y   Ibs/in.,  so  that  f i x )   ^   - k ,   a
                                  constant.  The  equation  of motion  then  takes  the  form
                                                        "I'l                 ' 0 , '
                                                 ml  p   é     8 E / r ,   T  Ox  Qz

                                                           ’  +  7 T  [^</]  ‘  > =  <
                                                         '■1 ,         ^'3   Qz
                                                                             .04.
                                  Evaluating  the  integral  in  Eq.  (10.8-3)  for  an  element  of  length  /,  we  have
                                                 "0.3714   0.524/  0.1286  -0.03095/   "
                                                         0.009524/'  0.03095/  -0.007143/'
                                        {0,}  =  -kl              0.3714   -0.05238/  <
                                                                            0.009524/'
                                  When  applied  to  this  problem  with  1  =  1/2  and  transferred  to  the  left  side  of  the
                                  equation,  the  stiffness  of  the  beam  is  increased.










                                                                (D   Figure  10.8-1.
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