Page 492 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 492

Sec. 14.8   Runge-Kutta Method                                 479


                                  then  represents  one  type  of  self-excited  oscillation  and  the  amplitude  continues  to
                                  increase.
                                       The work done  by the  spring from  2 to 3  is
                                                 -^/c[(jT()  +  Ax)  -(-  (X()  -   2x)](2x  +  Ax)
                                  The work done  by friction  from  2 to 3  is
                                                          /x^,mg(2x  +  Ax)
                                  Equating the net work done between 2 and 3 to the change in kinetic energy, which is

                                                    -^/c(2X()  -   2x   Ax)  + ix,^,mg =  0   (c)
                                  By substituting (a) and (b) into (c), the increase  in amplitude per cycle of oscillation is
                                                                    -  ^^kl)
                                                         ^x  =                               (d)


                       14.8  RUNGE-KUTTA METHOD

                              The  Runge-Kutta  method  discussed  in  Chapter 4 can  be  used  to  solve  nonlinear
                              differential  equations.  We consider the  nonlinear equation
                                              d'-x   . . d x       ,   . .    . .
                                                  +  0.4  -1— h X  +  0.5x^  =  0.5 cos 0.5r
                                              dr^      dr
                              and rewrite  it in first-order form by letting  y  =  dx/dr  as follows:
                                          ^   =  0.5 cos 0.5r  -  x  -   0.5x^  -   0.4y  = E (r, x, y)

                              The computational  equations to be  used are programmed for the digital computer
                              in  the following order:



                                  t\=r^                       gx=y\          /i  =  H /j,/c i, ^i)
                                  t^  =  T ^+h /2  k2=x^y-g^h/2  g2=y^-yfyh/2  f2  =  F(t2,k2,g2)

                                  ^3 =   T,  +   /t/2  k^  =   Xd^  y-  g 2 h / 2    g 3= y ,   + / 2 /z/ 2   /3   =  ^ 3)
                                  t^  =   T  +   h   / C 4 - X ,   + ^ 3 / 1    ^ 4 = ^ 1   + / 3^   /4 =   H f 4 ,   /C4,  g4)
                              From  these  results,  the  values  of  x  and  y  are  determined  from  the  following
                              recurrence  equations, where  h  =  At:
                                               X,+ l  -       +  2^2  +  2g3  + ^4)      (14.8-2)

                                               y i + \   ^   yi  F   -^ (/i  +  2 /2   +  2 /3   + f ^ )  (14.8-3)
                              Thus, with  /  =  1,  X2  and  y2  are found,  and with  T2  =  Tj  +  A t , the previous table
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