Page 320 - Thermodynamics of Biochemical Reactions
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320      Mathematica Solutions to Problems



                {3,  8,  41

        Note that Mathernatica makes no distinction between "row" and "column" vectors.

         (d)  Calculate the amounts of the components CO, H, , and CH4 for the system containing one mole of each of the five species.

                ared.{l,l,l,l,l}



         Note that the amount of a component can be negative.


        5.2  (a)  Construct the conservation matrix for the hydrolysis of  ATP to ADP in terms of  species.  (b)  Calculate a basis for
         the stoichiometric matrix from the conservation matrix and show that it is consistent with equations 5.1-28 to 5.1-31.

         (a)  Construct the conservation matrix for the hydrolysis of ATP to ADP in terms of species.


                a={{10,0,0,0,10,10,10,0},  {12,1,2,1,12,13,13,2},  {13,0,1,4,10,13,10,4},  {3,0,0,1,2,3,2,111
                ;
                                                                 {
                TableForm[a,TableHeadings-> { { "C" , "H" , "0" , "P" } , "ATPI-", "H+" , "H20", "HP042-", "mP3-
                  iiHATP3- WADP2- I*, "H2P04- 1 1, Tablespacing-> E 1,1.5 1 I
                          I#,
                    ATP4-  H+  H20  HP042-  ADP3-  HATP3-  HADP2-  H2P04-
                c   10      0   0    0        10     10       10       0
                H   12      1   2    1        12     13       13      2
                0  13       0   1    4        10     13       10       4

                P   3       0   0    1        2      3        2        1
                TableForm[RowFleduce [a] ,TableHeadings->{ { "ATP4-", "H+", 1'H20", 1'HP042-"}, ("ATP4-
                'I,  'H+", "H20", 11HP042-11, "ADP3- 11,  "HATP3- 'I,  "KADPS- 'I,  "H2PO4- } 1, Tablespacing-> { 1,l. 5 11

                          ATP4-  H+  H20  HP042-  ADP3-  HATP3-  HADP2-  H2P04-
                ATP4-     1      0   0     0       1       1       1        0
                H+        0      1   0     0       -1      1       0        1
                H2 0      0      0   1     0       1       0       1        0

                HP042-    0      0   0     1       -1      0       -1       1
         (b)  Calculate a basis for the stoichiometric matrix from the conservation matrix and show that it is consistent with equations
         5.1-28 to 5.1-31.

                                           1
                TableForm[nu=~llSpace [a]
                0    -10  -         1  0   0   0  1
                -10  -11  0               0   1   0
                -1-10  0             0    1   0   0
                -11  -11  1               0   0   0

         The transposed stoichiometric matrix for reactions 5.1-28 to 5.1-31 is

                nutrexpected={E-l,l,-l,l,l,O,O,O},{l,l,O,O,O,-l,O,O},{O,l,O,O,l,O,-l,O},~O,l,O,l,O,O,O,
                -111;
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