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§4.4  Flow near Solid  Surfaces  by  Boundary-Layer  Theory  137

     SOLUTION              We  know  intuitively  what  the velocity  profile  v {y) looks  like. Hence we  can guess a form  for
                                                                 x
                           v (y) and substitute it directly into the von Karman momentum balance. One reasonable choice
                            x
                           is  to  let  v (y)  by  a  function  of  у 18, where  8{x) is  the  "thickness"  of  the boundary  layer.  The
                                  x
                           function  is  so chosen that v x  = 0 at у  = 0 and v x  = v  at у  = 8. This is tantamount to  assuming
                                                                    c
                           geometrical  similarity  of  the velocity  profiles  for  various  values  of x. When  this assumed  pro-
                           file  is substituted  into the von  Karman momentum balance, an ordinary  differential  equation
                           for  the boundary-layer  thickness 8(x) is obtained. When  this equation has been solved,  the 8(x)
                           so obtained can then be used  to get the velocity  profile  and other quantities  of interest.
                              For the present problem a plausible  guess  for  the velocity  distribution, with  a reasonable
                           shape, is
                                         ЗУ
                                         25            for  0 < у  < 8(х)  (boundary-layer  region)  (4.4-14)
                                                       for  у  >8(х)    (potential flow  region)  (4.4-15)

                           This  is  "reasonable"  because  this  velocity  profile  satisfies  the no-slip  condition at у  = 0, and
                           Sv /dy  = 0 at  the outer edge  of  the boundary  layer.  Substitution  of  this  profile  into the von
                             x
                           Karman integral balance in Eq. 4.4-13 gives
                                                              a  ( i  39  2 *
                                                          8    =  V Tx[2S6 pVx8                (4.4-16)

                           This first-order,  separable  differential  equation can now  be integrated  to give  for  the bound-
                           ary-layer  thickness

                                                                                               (4.4-17)

                           Therefore, the boundary-layer  thickness increases as the square root of the distance from  the up-
                           stream end  of the plate. The resulting approximate solution for the velocity  distribution is then

                                                                                               (4.4-18)

                           From this result  we  can estimate the drag  force  on a plate  of  finite  size wetted  on both  sides.
                           For a plate of width  W and length  L, integration of the momentum flux  over the two solid  sur-
                           faces  gives:

                                                                 dxdz  =  1.293                (4.4-19)
                                                               ./ = 0
                           The exact solution, given  in the next example, gives the same result, but with  a numerical co-
                           efficient  of  1.328. Both solutions  predict the drag  force  within  the scatter  of  the experimental
                           data. However, the exact solution gives somewhat better agreement with  the measured  veloc-
                           ity profiles. 3  This additional accuracy is essential  for  stability  calculations.

       EXAMPLE  4.4-2      Obtain the exact solution  for  the problem given  in the previous  example.

     Laminar Flow along    SOLUTION
     a Flat Plate  (Exact
     Solution)'            This problem  may  be solved  by  using  the definition  of  the stream  function  in Table 4.2-1. In-
                           serting  the expressions  for  the velocity  components in the first row  of entries, we  get
                                                                         ъ
                                                                 2
                                                         2
                                                     дф  д ф  дф  д ф  _  д ф
                                                                                               (4.4-20)
                                                     ду  дхду  дХ  Jy 2  А У Ъ
                               7
                                This problem was  treated originally by  H. Blasius, Zeits.  Math.  Phys., 56,1-37 (1908).
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