Page 110 - Trenchless Technology Piping Installation and Inspection
P. 110

76    Cha pte r  T w o

            a. Determine load
                                      w ×  H ×  R
                       q = 0 433 ×  H +    s   w  + W
                           .
                        t          w               s
                                          144
                                  ⎛ H ⎞
                      R = 10 33–.  × ⎜  w ⎟
                        w
                                  ⎝ H s ⎠
                      R  = 0.835
                        w
                       w = 120 pcf
               1. Live load
                 a. Concentrated
                                           ×
                                033 × C ×  P F
                                 .
                           W =         sc     sc
                             sc
                                     12  ×  D
          where  W  = concentrated live load, psi
                  sc
                  P = concentrated load, lb
                 F  = impact factor (concentrated)
                  sc
                 C  = load influence coefficient (concentrated)
                  sc
                  D =  inside diameter of existing pipe (or liner pipe outside
                     diameter), in.
                 b. Distributed
                                   C ××
                                       p F
                             W =    sd     sd
                               sd
                                      144
          where  W  = distributed live load, psi
                  sd
                  p = applied surface load, psf
                 F  = impact factor (distributed)
                  sd
                 C  = load influence coefficient (distributed)
                  sd
                  D =  inside diameter of existing pipe (or outside diameter), in.
          Concentrated L.L  P =  16,000 lb
                          C   =  0.03826 (Table 2.12)
                           sc
                          F  =  1.00
                           sc
          Distributed L.L   P =  0 psf
                          C   =  0.000 (Table 2.12)
                           sd
                          F  =  0.00
                           sd
                              .
                                         ,
                        .
                                                = 035.
                  W =  0 33  × 0 03826  × 16 000  × 1     psi
                    sc
                                   × 48
                                12
                        .
                 W   =  0 000  × 0  × 0  = 000.    psi
                   sd      144
                   W  = W  + W = 0.35 psi
                    s    sc   sd
               2.  Total external load
                       .
                              .
                                                     .
                   q = 0 433  × 8 00 +  120  × 16  × 0.835  + 035
                    t
                                         144
                   q  = 14.90 psi
                    t
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