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2-16   WATER AND WASTEWATER ENGINEERING

                            that it assumes that the sequence of events leading to a drought or flood will be the same in the
                            future as it was in the past. More sophisticated techniques have been developed to overcome this
                            disadvantage. These techniques are left for advanced hydrology classes.
                                 The Rippl procedure for determining the storage volume is an application of the mass bal-
                            ance method of analyzing problems. In this case it is assumed that the only input is the flow into
                            the reservoir ( Q     in   ) and that the only output is the flow out of the reservoir ( Q     out   ). Therefore,with
                            the assumption that the density term cancels out because the change in density across the reser-
                            voir is negligible,
                                                           dS   d()In  d(Out )
                                                                                                         (2-2)
                                                           dt    dt      dt
                            becomes

                                                         dS
                                                               Q   out                                   (2-3)
                                                                   Q
                                                               in
                                                         dt
                              If both sides of the equation are multiplied by  dt,  the inflow and outflow become volumes (flow
                            rate     time     volume), that is,
                                                                         dt
                                                                   Q
                                                          Q )()
                                                    dS  ( in  dt  ( out  )()                             (2-4)
                                By substituting finite time increments (  t ), the change in storage is then

                                                                      )
                                                           ) (Qout
                                                    (Qin )( t     )( t     S                             (2-5)
                                By cumulatively summing the storage terms, the size of the reservoir can be estimated. For
                            water supply reservoir design,  Q     out    is the demand, and zero or positive values of storage (  S )
                            indicate there is enough water to meet the demand. If the storage is negative, then the reservoir
                            must have a capacity equal to the absolute value of cumulative storage to meet the demand. This
                            is illustrated in the following example.


                              Example 2-3.   Using the data in  Table 2-7 , determine the storage required to meet Nosleep’s
                                           3
                            demand of 0.25 m  /s for the period from August 1994 through January 1997.
                              Solution.   The computations are summarized in the table below.


                                        Q in    (0.05)(Q in )   (0.05)(Q in )( t)  Q out    Q out ( t)    S   S ( S)
                                         3         3           6  3        3        6  3      6  3      6  3
                            Month      (m /s)   (m /s)      (10  m )    (m /s)   (10  m )   (10  m )  (10  m )
                            1994
                              Aug       1.70    0.085        0.228       0.25     0.670      0.442     0.442
                              Sep       1.56    0.078        0.202       0.25     0.648      0.446     0.888
                              Oct       1.56    0.078        0.209       0.25     0.670      0.461     1.348
                              Nov       2.04    0.102        0.264       0.25     0.648      0.384     1.732
                              Dec       2.35    0.1175       0.315       0.25     0.670      0.355     2.087
                                                                                                   (continued)
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