Page 56 - Petroleum Production Engineering, A Computer-Assisted Approach
P. 56

Guo, Boyun / Petroleum Production Engineering, A Computer-Assisted Approach  0750682701_chap04 Final Proof page 47 22.12.2006 6:07pm




                                                                                 WELLBORE PERFORMANCE  4/47
                           0.1                                                           Relative Roughness

                                                                                                0
                          0.09
                                                                                                0.000001
                                                                                                0.000005
                                                                     Turbulent Flow
                          0.08
                                                                                                0.00001
                                                                                                0.00005
                          0.07
                                                                                                0.0001
                                                                                                0.0002
                          0.06
                                                                                                0.0004
                         Friction Factor  0.05                                                  0.0006


                                                                                                0.001


                          0.04                                                                  0.002
                                                                                                0.004
                                                                                                0.006
                          0.03
                                       Laminar                                                  0.01
                                        Flow
                                                                                                0.015
                          0.02
                                                                                                0.02

                                                                                                0.03
                          0.01
                                                                                                0.04
                                                                                                0.05
                             0
                            1.E+02   1.E+03   1.E+04    1.E+05   1.E+06   1.E+07   1.E+08
                                                    Reynolds Number
                              Figure 4.2 Darcy–Wiesbach friction factor diagram (used, with permission, from Moody, 1944).



                                                                                    2:259
                       Solution Oil-specific gravity:                           D ¼
                                                                                     12
                                           141:5                                  ¼ 0:188 ft:
                                     g o ¼
                                          API þ 131:5
                                          141:5                  Fluid velocity can be calculated accordingly:
                                       ¼                                         4q
                                        40 þ 131:5                           u ¼
                                       ¼ 0:825                                  pD 2
                                                                                 4(5:615)(1,000)
                                                                               ¼
                       Oil density:                                             p(0:188) (86,400)
                                                                                      2
                                                                               ¼ 2:34 ft=s:
                                     r ¼ 62:4g o
                                      ¼ (62:5)(0:825)
                                                                 Reynolds number:
                                      ¼ 51:57 lb m =ft 3
                                                                                 1:48qr
                       Elevation increase:                                  N Re ¼
                                                                                  dm
                                    DZ ¼ cos (a)L                                1:48(1,000)(51:57)
                                                                               ¼
                                       ¼ cos (15)(1,000)                           (2:259)(1:2)
                                       ¼ 966 ft
                                                                               ¼ 28,115 > 2,100, turbulent flow
                           7
                       The 2 ⁄ 8 -in., 8:6-lb m =ft tubing has an inner diameter of
                       2.259 in. Therefore,                      Chen’s correlation gives
   51   52   53   54   55   56   57   58   59   60   61